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Yakvenalex [24]
2 years ago
6

Why do stars appear so steady when viewed from the surface of moon or by an astronaut in space?

Physics
1 answer:
Nutka1998 [239]2 years ago
4 0

Answer:

Explanation:

The light from these little disks is also refracted by Earth's atmosphere, as it travels toward our eyes. That's because, in the direction of any horizon, you're looking through more atmosphere than when you look overhead. If you could see stars and planets from outer space, both would shine steadily.

Answer From GauthMath If you like it then please heart it and comment thanks.

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Complete the sentences below using the words below, you may use each word more than once
satela [25.4K]
Decreases, stays the same, increases. The volume decreases because as air is cooled, the individual molecules collectively possess less kinetic energy and the distances between them decrease, thus leading to a decrease in the volume they occupy at a certain pressure (please note that my answer only holds under constant pressure; air, as a gas, doesn't actually have a definite volume). The mass stays the same because physical processes do not create or destroy matter. The law of conservation of mass is obeyed. You're only cooling the air, not adding more air molecules. The density decreases because as the volume decreases and mass stays the same, you have the same mass occupying a smaller volume. Density is mass divided by volume, so as mass is held constant and volume decreases, density increases.
7 0
3 years ago
Why won’t anyone help me please anybody help me I really need help .
irga5000 [103]

Answer:

1➡️ this is the method of decomposition

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2 years ago
.<br> What happens to the average kinetic energy of water molecules as water freezes?
leva [86]

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3 years ago
Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.84 keV from the co
ElenaW [278]

Answer:

λ  = 65.6 pm

Explanation:

Given that

λo = 65 pm

The initial energy of the electron

E_o=\dfrac{hC}{\lambda_0 }

Now by putting the values

E_o=\dfrac{hC}{\lambda_0 }

E_o=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{65\times 10^{-12}}

E_o=3.05\times 10^{-15}\ J

E_o=\dfrac{3.05\times 10^{-15}}{1.6\times 10^{-19}\times 10^3}\ KeV

Eo=19.06 KeV

Given that kinetic energy KE= 0.84 KeV

Therefore the final energy

E= Eo - KE

E = 19.06 - 0.84 KeV

E= 18.22 KeV

The wavelength  λ can be find as

E=\dfrac{hC}{\lambda}

\lambda=\dfrac{hC}{E}

\lambda=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{19.06 \times 10^3\times 1.6\times 10^{-19}}

λ = 6.56 x 10⁻¹¹ m

λ  = 65.6 pm

3 0
3 years ago
The fundamental resolution of a lens or telescope is determined by:
Sliva [168]

Answer:

The numerical aperture of the lens.

Explanation:

A numerical aperture is a dimensionless number that is the range of angles that the system can accept / emit light.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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2 years ago
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