Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es = \sqrt{ \frac{p(1-p)}{n} }
where
n = the sample size.
The margin of error is
E=z^{*}E_{s}
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
Remaining area of poster = Area of Big rectangle - Area of small rectangle
= (36*24) - (5*12) =
= 864 - 60 = 804 in^2
Answer:
They bought 6.24 pounds of hamburger meat
Explanation:
We are given that:
The first friend brought 2.7 pounds of hamburger meat
The second friend brought 3.54 pounds of hamburger meat
The total amount of hamburger meat they both brought would be simply the summation of what they brought individually.
This means that:
Total amount brought = 2.7 + 3.54
Total amount brought = 6.24 pounds of hamburger meat
Hope this helps :)
