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4 years ago

7

A proton travels with a speed of 4.90 106 m/s at an angle of 56° with the direction of a magnetic field of magnitude 0.250 T in

the positive x-direction. What is the magnitude of the magnetic force on the proton?

1 answer:

Sloan [31]4 years ago

7 0

Answer:

F = 1510.21 x 10^-16N

Explanation:

F = Bqv Sin (angle)

F = 0.250 x 1.6 x 10^-19 x 4.9 x 10^6 x sin(56)

F = 1510.21 x 10^-16N

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To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit

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To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as

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$a_t = 1.1ft/s^2$

PART A )

$a_c = \frac{V^2}{R}$

$a_c = \frac{V^2}{350}$

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $5.25ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

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Now calculate the angular velocity of the motorcycle

$v = r\omega$

$42.3877 = 350\omega$

$\omega = 0.1211rad/s$

Calculate the angular acceleration of the motorcycle

$a_t = r\alpha$

$1.1 = 350\alpha$

$\alpha = 3.1428*10^{-3}rad/s^2$

Calculate the time needed by the motorcycle to reach an acceleration of

$5.25ft/s^2$

$\omega = \alpha t$

$0.1211 = 3.1428*10^{-3}t$

$t = 38.53s$

PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

PART C)

Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a_r = \frac{v^2}{R}$

$a_r = \frac{21.5^2}{350}$

$a_r =1.3207ft/s^2$

Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a = \sqrt{a_t^2+a_r^2}$

$a = \sqrt{(1.1)^2+(1.3207)^2}$

$a = 1.7187ft/s^2$

PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

3 0

3 years ago

Pls help me I will make you as Brainly

Helga [31]

Answer:

D

Explanation:

6 0

3 years ago

Read 2 more answers

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molec

Vlad1618 [11]

Complete Question

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as $N=1/\lambda\ cm^{-1}$ )

Answer:

The ratio of intensities is $I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774$

Explanation:

From the question we are told that

The number of sets of satellite is $n = 4$

The temperature is $T = 27 ^oC$

The resonant infrared frequencies are $f_1 = 217 cm^{-1}$

$f_2 = 315 cm^{-1}$

$f_3 = 457 cm^{-1}$

$f_4 = 774 cm^{-1}$

From the question we see that the wave number also has a unit of $cm^{-1}$ hence the value of the wave numbers of the molecule are

$N_1 = 217 cm^{-1}$

$N_2 = 315 cm^{-1}$

$N_3 = 457 cm^{-1}$

$N_4 = 774 cm^{-1}$

Generally intensity is mathematically represented as

$I = \frac{nhc}{A \lambda }$

Here we see that I varies inversely with wavelength i,.e

$I \ \ \alpha \ \ \frac{1}{\lambda }$

From the question we are told that the wave number is mathematically represented as

$N = \frac{1}{\lambda }$

Therefore

$I \ \ \alpha \ \ N$

This implies that the ratio of intensity in first set to that of second set to that of third set to that of fourth set is equal to the ratio of the wavenumber in the first set to that of the second set to that of third set to that of fourth

This is mathematically represented as

$I_1 : I_2 : I_3 : I_4 = N_1 : N_2 : N_3 : N_4$

Substituting values

$I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774$

5 0

4 years ago