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V125BC [204]
4 years ago
7

A proton travels with a speed of 4.90 106 m/s at an angle of 56° with the direction of a magnetic field of magnitude 0.250 T in

the positive x-direction. What is the magnitude of the magnetic force on the proton?
Physics
1 answer:
Sloan [31]4 years ago
7 0

Answer:

F = 1510.21 x 10^-16N

Explanation:

F = Bqv Sin (angle)

F = 0.250 x 1.6 x 10^-19 x 4.9 x 10^6 x sin(56)

F = 1510.21 x 10^-16N

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Mechanical (sound) waves to Earth from satellites. How is this possible? aves are unable to travel through a vacuum, such as thr
Anuta_ua [19.1K]

Sound waves are not able to travel in a vacuum, sound requires a medium such as air or a solid for example.  Satellites are indeed in space, but radio waves are not sound waves they are a form of light.  Light can travel in a vacuum so the messages that satellites beam back to Earth are light waves not sound waves, that is why it is possible.

6 0
3 years ago
A common way to measure the distance to lightning is to start counting, one count per second, as soon as you see the flash. Stop
AURORKA [14]

Answer:

d = 1.07 mile

Explanation:

The rationale for this method is that the speed of light is much greater than the speed of sound, the definition of speed in uniform motion is  

v = d / t  

d = v t  

the speed of sound is worth  

v = 343 m / s  

Therefore, the speed of sound must be multiplied by time to do this, all the units must be in the same system, as the distance in miles is requested  

v = 343 m/s (1mile/1609 m) (3600s/1 h) = 343 (2.24) = 767.4 mile/h  

v = 343 m / s (1 mile / 1609 m) = 0.213, mile/ s  

If the measured time is t = 5s we multiply it by the speed  

we substitute  

d = 0.213 5

d = 1.07 mile

If you want to calculate the speed, this method in general is not widely used, since you must know the distance where the lightning occurred, which is relatively complicated.

8 0
3 years ago
If a ball leaves the ground with a vertical velocity of 5.46 m/s, how long does it take
kifflom [539]

Answer:

0.557 s

Explanation:

Given:

v₀ = 5.46 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 5.46 m/s

t = 0.557 s

8 0
4 years ago
A fluid moves through a tube of length 1 meter and radius r=0.002±0.0002 meters under a pressure p=4⋅105±1750 pascals, at a rate
yaroslaw [1]

Answer:

The  maximum error is  \Delta  \eta  = 2032.9

Explanation:

From the question we are told that

     The length  is  l  =  1\ m

      The radius is  r =  0.002 \pm  0.0002 \ m

        The pressure is  P  =  4 *10^{5} \ \pm 1750

        The  rate  is  v =  0.5*10^{-9} \ m^3 /t

       The viscosity is  \eta  =  \frac{\pi}{8} * \frac{P *  r^4}{v}

The error in the viscosity is mathematically represented  as

       \Delta  \eta  = | \frac{\delta \eta}{\delta P}| *  \Delta  P   +    |\frac{\delta \eta}{\delta r} |*  \Delta  r +  |\frac{\delta \eta}{\delta v} |*  \Delta  v

   Where  \frac{\delta \eta }{\delta P} =  \frac{\pi}{8} *  \frac{r^4}{v}

and         \frac{\delta \eta }{\delta r} =  \frac{\pi}{8} *  \frac{4* Pr^3}{v}

and          \frac{\delta \eta }{\delta v} =  - \frac{\pi}{8} *  \frac{Pr^4}{v^2}

So  

             \Delta  \eta  = \frac{\pi}{8} [ |\frac{r^4}{v}  | *  \Delta  P   +    | \frac{4 *  P * r^3}{v}  |*  \Delta  r +  |-\frac{P* r^4}{v^2}  |*  \Delta  v]

substituting values

            \Delta  \eta  = \frac{\pi}{8} [ |\frac{(0.002)^4}{0.5*10^{-9}}  | *  1750   +    | \frac{4 *  4 *10^{5} * (0.002)^3}{0.5*10^{-9}}  |*  0.0002 +  |-\frac{ 4*10^{5}* (0.002)^4}{(0.5*10^{-9})^2}  |*  0 ]

  \Delta  \eta  = \frac{\pi}{8} [56  +  5120 ]

   \Delta  \eta  = 647 \pi

    \Delta  \eta  = 2032.9

4 0
4 years ago
A dogsled team has a total momentum of 1710 kg•m/s. If the team has a total mass of 450 kg, what is its speed?
HACTEHA [7]

Answer:

3.8 m/s

Explanation:

Momentum is the product of mass and velocity hence

Momentum=mv where m is mass and v is the velocity of an object

Making v the subject of the formula then

v=\frac {momentum}{m}

Substituting 1710 kgm/s for momentum and 450 Kg for mass we obtain

v=\frac {1710 Kgm/s}{450 Kg}=3.8 m/s

Hence the speed of dogsled team is 3.8 m/s

7 0
3 years ago
Read 2 more answers
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