Water is capable of dissolving a variety of different substances, and is attracted to many other different molecules
Answer:
F = 160.0 N
Explanation:
Given: Soccer payer with a mass = 80 kg, force = 20 N
To find: force
Formula: 
Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.
F = m × a
F = 20 kg - 10 = 2
F = 80 × 2 = 160
F = 160.0 N
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
Answer:
Hydrogen gas/bubbles
Explanation:
Photosynthesis is defined as the process by which green plants and other organisms like blue-green algae etc. synthesize organic matter. In the presence of light energy, they convert CO2 and H2O into organic sugar with the release of O2 gas.
The plant was performing photosynthesis since there is the presence of CO2 (baking soda) and water and therefore the bubbles seen is hydrogen gas guven off from photosynthesis .
6CO2(g) + 6H2O(l) --> C6H12O6(s) + 6O2(g)
Answer:
The change in potential energy of the mass as it goes up the incline is 0.343 joules.
Explanation:
We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:
Where:
- Gravitational potential energy, measured in Joules.
- Mass, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
- Change in vertical height, measured in meters.
This work is the energy needed to counteract effects of gravity at given vertical displacement.
If we know that 
, 
and 
, the change in the potential energy of the mass as it goes up the incline is:
The change in potential energy of the mass as it goes up the incline is 0.343 joules.
Answer:
Its resistance decreases
Explanation:
The resistance of a wire is directly proportional to the length of the wire and inversely proportional to the cross sectional area of the wire.
Mathematically,
R1 =¶L1/A1... (1)
R1= ¶L1/{Πd²/4}
R1= 4¶L1/Πd²
where;
¶ is the constant of proportionality which is the resistivity of the material
L is the length of the wire
A is the cross sectional area
A1 = Πd²/4
If the length is quadrupled and its diameter tripled
The new length L2 will be 4L1
New area A2 = Π(3d)²/4 = 9Πd²/4
The resistance will become
R2 = ¶(4L1)/{9Πd²/4}
R2 = 4¶L1×4/9Πd²
R2 = 16¶L1/9Πd²... (2)
R2/R1 = 16¶L1/9Πd²÷4¶L1/Πd²
R2/R1 = 16¶L1/9Πd²×Πd²/4¶L1
R2/R1 = 16/9×1/4
R2/R1 = 16/36
R2/R1 = 4/9
R2 = 4/9R1
This shows that the resistance of the wire decreases
