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Alenkinab [10]
3 years ago
7

3. A Beer's law plot for Cu2+ was experimentally obtained. The slope of the Beer's law plot was 435 L/mol (with a y-intercept =

0.001). A Cu2+ solution of unknown concentration had an absorbance of 0.75. What is the molar concentration of Cu2+ in the unknown solution?
Chemistry
1 answer:
ozzi3 years ago
7 0

Answer:

0.00172 M

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

l is the path length

\epsilon is the molar absorptivity

c is the concentration.

If a graph is plotted between the concentration and absorbance, then the slope is:- \epsilon l. So,

c=\frac{A}{slope}=\frac{0.75}{435}\ M=0.00172\ M

<u>0.00172 is the molar concentration of Cu^{2+} in the unknown solution.</u>

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Answer:

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5. A penny weighs about 2.5 g. How many moles of pennies would be required to equal the mass of the moon (7.3x10^24 kg)
schepotkina [342]

5. 1.16 x 10^{26} moles  moles of pennies would be required to equal the mass of the moon.

6. 12.86 moles of ethanol are in a 750 ml bottle of vodka.

Explanation:

5 .Data given:

mass of penny = 2.5 grams

atomic mass of penny = 62.93 grams/mole

moles present in mass of the moon given as = 7.3 x 10^{24} kg

number of moles = \frac{mass}{atomic mass of  1 mole}

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0.039 moles of penny is present in 2.5 grams

0.039 moles of penny in 2.5 grams of it

so, x moles in 7.3 X 10^{27}  grams

\frac{0.039}{2.5} =\frac{x}{7.3 X 10^{27} }

x = 1.16 x 10^{26} moles

so when the mass of the penny given is equal to the mass of moon, number of moles of penny present is 1.1 x 10^{26} .

6.

Given:

vodka = 40% ethanol

volume of vodka bottle = 750 ml

moles of ethanol =?

density of ethanol =0.79 g/ml

atomic mass of ethanol = 46.07 grams/mole

so, from the density of ethanol given we can calculate how much ethanol is present in the solution.

density = \frac{mass}{volume}

density x volume = mass

0.79 x 750 = 592.5 grams

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles of ethanol = \frac{592.5}{46.07}

                                               = 12.86 moles of ethanol

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3 years ago
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A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal
devlian [24]

Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

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The mass of metal X in the two oxides will be the same because it's the same metal.

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X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

6 0
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