The answer is- Gasoline - homogeneous, Soil- heterogeneous, Cranberry juice - homogeneous and Salt water-homogeneous.
Mixture: The substance that has two or more elements or compounds mixed together without binding them chemically is known as mixture.
The constituents of mixture can be separated by various methods.
What are homogeneous and heterogeneous mixture?
- Homogeneous mixtures- Homogeneous mixtures are those that have same composition throughout its mass and there are no visible boundaries between its components.
- Heterogeneous mixtures- When solute particles are not mixed uniformly in the solvent particles, then a heterogenous mixture is obtained.
- Gasoline: It is a homogeneous mixture of various hydrocarbons.
- Soil: Soil is a heterogenous mixture and its various components can be seen clearly.
- Cranberry juice: It is also a homogeneous mixture as cranberry and water are mixed uniformly.
- Salt water is also a homogeneous mixture as salt and water are mixed uniformly.
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I'd say true.
Matter is a physical substance that occupies space.
Lets say you put random stuff in a box. That stuff is matter, filling the box.
Its common to say that matter is everything around you. You can see everything around you (almost).
Answer:
1. A
2. B
Explanation:
1. Most of the answers don't make that much sense, so using process of elimination I resulted in this answer. I recommend you also try to check with others.
2. This question also was pretty confusing but when using process of elimination I resulted in either A or B. To me B makes more sense.
The standard addition equation is as followsI_(S+X) (V/V_O )=I_X+I_X/[X]_i [S]_4 (V_S/V_0 ) Here, [X]_i is the initial concentration of analyte, [S]_i is the initial concentration of standard, I_X is signal for analyte, I_(S+X) is signal for standard and analyte, V_0 is the initial volume, V_S is the added standard volume, and V is the total volume.Added volume of standard V_S is-23.3 mL. Initial volume of the sample V_0 is 10.00 mL. Initial concentration of standard ([S]_i) is 0.156 ng/mL.[X]_i= -[S]_i (V_S/V_0 )〖[X]〗_(i )= -(0.156 ng/mL)((-23.3 mL)/(10.00 mL))=0.363 ng/mL
Concentration of U(III) in ground sample is 0.363 ng/mL
So boron has an electronic configuration of 1S2 2S2 2P1 and the element with an atomic number of 3 is Lithium which has an electronic configuration of 1S2 2S1.
So the answer is 1S2 2S1.
