Answer:
![P=3.7atm](https://tex.z-dn.net/?f=P%3D3.7atm)
Explanation:
Hello,
In this case, it is possible to determine the pressures of both helium and neon as shown below:
![n_{He}=\frac{P_{He}V_{He}}{RT}=\frac{5.6atm*3.0L}{0.082\frac{atm*L}{mol*K}*298.15K} =0.688molHe\\\\n_{Ne}=\frac{P_{Ne}V_{Ne}}{RT}=\frac{3.6atm*4.5L}{0.082\frac{atm*L}{mol*K}*298.15K}=0.663molNe](https://tex.z-dn.net/?f=n_%7BHe%7D%3D%5Cfrac%7BP_%7BHe%7DV_%7BHe%7D%7D%7BRT%7D%3D%5Cfrac%7B5.6atm%2A3.0L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298.15K%7D%20%3D0.688molHe%5C%5C%5C%5Cn_%7BNe%7D%3D%5Cfrac%7BP_%7BNe%7DV_%7BNe%7D%7D%7BRT%7D%3D%5Cfrac%7B3.6atm%2A4.5L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298.15K%7D%3D0.663molNe)
Now, one considers the total moles (addition between both neon's and helium's moles) and the total volume to compute the final pressure as shown below:
![P=\frac{n_TRT}{V_T} =\frac{(0.688+0.663)mol*0.082\frac{atm*L}{mol*K}*298.15K}{9.0L}=3.7atm](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bn_TRT%7D%7BV_T%7D%20%3D%5Cfrac%7B%280.688%2B0.663%29mol%2A0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298.15K%7D%7B9.0L%7D%3D3.7atm)
Best regards.
Answer:
The wavelength of wave is 0.33 ×10²⁰ m.
Explanation:
Given data:
Frequency of wave = 9.12×10⁻¹² Hz
Wavelength of wave = ?
Solution:
Formula:
Speed of light = wavelength × frequency
c = λ × f
λ = c/f
This formula shows that both are inversely related to each other.
The speed of light is 3×10⁸ m/s
Frequency is taken in Hz.
It is the number of oscillations, wave of light make in one second.
Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.
Now we will put the values in formula.
λ = 3×10⁸ m/s / 9.12×10⁻¹² Hz
Hz = s⁻¹
λ = 0.33 ×10²⁰ m
The wavelength of radiation is 0.33 ×10²⁰ m .
Catalysts speed up a reaction so it would be the reaction rate increases.
Clean? I’m pretty sure not sure what it means but.
Answer: 1560632 joules
Explanation:
The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Given that:
Q = ?
Mass of frozen water (ice) = 1kg
C = 4184 J/(kg K)
Φ = (Final temperature - Initial temperature)
= 100°C - 0°C = 100°C
Convert 100°C to Kelvin
(100°C + 273) = 373K
Then, Q = MCΦ
Q = 1kg x 4184 J/(kg K) x 373K
Q = 1560632 joules
Thus, the change in thermal energy is 1560632 joules