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lorasvet [3.4K]
3 years ago
8

Jupiter’s moon io was discovered to have high concentrations of sulfur oxides in its atmosphere. this, in combination with resea

rch into sulfur oxides relating to pollution on earth, has led to renewed interest in sulfur oxide compounds. one compound discovered on io was the blue disulfur trioxide. write the chemical formula for this compound.
Chemistry
2 answers:
Rasek [7]3 years ago
4 0
<span>S</span>₂O₃ -<span> disulfur trioxide</span>
Margarita [4]3 years ago
4 0

Answer:

S_2O_3

Explanation:

Hello,

Nomenclature, is a powerful tool in chemistry to name chemical compounds to successfully distinguish among the thousands and thousands of existing molecular compounds. In rule to stipulate a chemical name y is via specifying the amount of the composing elements into the molecule, thus, the prefix <em><u>di</u></em>, accounts for two atoms and the prefix <u><em>tri</em></u> for three (this is related with the valence electrons the element has), in such a way, disulfur trioxide is represented with two sulfur atoms and three oxygen atoms, this is:

S_2O_3

Which would be a novel molecule since the sulfur has been reported to have +2,+4 and +6 as the positive oxidation states which are possible to dovetail with oxygen as it is negative.

Kind regards.

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What would be the mass of a 33.5dm3 sample of O2 at STP?
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Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

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Which statement best describes an array of 10 elements where the elements are of a class type?
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How many atoms of gold are in gold nugget with a mass of 4.25 g
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Number of Atoms in Gold for given mass can be calculated using following formula,

              # of Moles  =  Number of Atoms / 6.022 × 10²³
Or,
             Number of Atoms  =  Moles × 6.022 × 10²³     ------- (1)    

Calculating Moles,
As,
                              Moles  =  Mass / M.mass
So,
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                              Moles  =  0.0215

Putting value of mole in eq.1,

             Number of Atoms  =  0.0215 × 6.022 × 10²³

             Number of Atoms  =  1.299 × 10²²

Result:
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