<u>Answer:</u> In the reaction, magnesium atoms lose electrons.
<u>Explanation:</u>
An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom. These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.
Magnesium is 12th element of the periodic table having electronic configuration of 
This element will loose 2 electrons to form 
ion
Chlorine is 17th element of the periodic table having electronic configuration of 
This element will gain 1 electron to form 
ion
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
The ionic compound formed is 
Hence, in the reaction, magnesium atoms lose electrons.
Answer:
2.82 g
Explanation:
Step 1: Write the balanced precipitation reaction
3 Ba(NO₃)₂ (aq) + Al₂(SO₄)₃ (aq) ⇒ 3 BaSO₄(s) + 2 Al(NO₃)₃(aq)
Step 2: Calculate the reacting moles of Ba(NO₃)₂
45.0 mL (0.0450 L) of 0.548 M Ba(NO₃)₂ react.
0.0450 L × 0.548 mol/L = 0.0247 mol
Step 3: Calculate the moles of Al₂(SO₄)₃ that react with 0.0247 moles of Ba(NO₃)₂
The molar ratio of Ba(NO₃)₂ to Al₂(SO₄)₃ is 3:1. The reacting moles of Al₂(SO₄)₃ are 1/3 × 0.0247 mol = 8.23 × 10⁻³ mol
Step 4: Calculate the mass corresponding to 8.23 × 10⁻³ moles of Al₂(SO₄)₃
The molar mass of Al₂(SO₄)₃ is 342.2 g/mol.
8.23 × 10⁻³ mol × 342.2 g/mol = 2.82 g
Answer: 6.98
The Relative Atomic Mass of Li = (98*7 + 2*6)/98+2
RAM of Li = (686+12)/100
RAM of Li= 6.98
Answer:
116 years
Explanation:
To solve this, we will use the half life equation;
A(t) = A_o(½)^(t/t_½)
Where;
A(t) is the amount of strontium left after t years;
A_o is the initial quantity of strontium that will undergo decay;
t_½ is the half-life of strontium
t is the time it will take to decay
We are given;
A(t) = 7.5 g
A_o = 120 g
From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29
Thus;
7.5 = 120 × ½^(t/29)
Divide both sides by 120 to get;
7.5/120 = ½^(t/29)
0.0625 = ½^(t/29)
In 0.0625 = (t/29) In ½
-2.772589 = (t/29) × (-0.693147)
(t/29) = -2.772589/(-0.693147)
t/29 = 4
t = 29 × 4
t = 116 years
