1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
3 years ago
11

Eric has just had a sandwich that contained the equivalent of 1.80 mol of glucose the standard molar entropy of reaction is 182

j k-1 mol-1. how much energy (in kj) is available for sustaining eric's muscular and nervous activity assuming a body temperature of 36.9oc
Physics
1 answer:
maxonik [38]3 years ago
7 0

Energy available for sustaining Eric's muscular and nervous activity can be calculated by,

Energy available= Standard molar entropy×Number of moles×Temperature

We have, standard molar entropy of glucose = 182 J/K mol

Number of moles of glucose = 1.80 mol

Body temperature = 36.9° C = 36.9 + 273.15 = 310.05 K

Substituting the value we get,

Energy available = 182×1.80×310.05 = 100,456.2 J

You might be interested in
Two point charges of -7uC and 4uC are a distance of 20
aivan3 [116]

Answer:

Approximately 0.979 J.

Explanation:

Assume that the two charges are in vacuum. Apply the coulomb's law to find their initial and final electrical potential energy \mathrm{EPE}.

\displaystyle \mathrm{EPE} = \frac{k \cdot q_1 \cdot q_2}{r},

where

  • The coulomb's constant k = 8.99\times 10^{9}\; \rm N\cdot m^{2} \cdot C^{-2},
  • q_1 and q_2 are the sizes of the two charges, and
  • r is the separation of (the center of) the two charges.

Note that there's no negative sign before the fraction.

Make sure that all values are in SI units:

  • q_1 = -7\rm \;\mu C = -7\times 10^{-6}\; C;
  • q_2 = 4\rm \;\mu C = 4\times 10^{-6}\; C;
  • Initial separation: \rm 20\; cm = 0.20\; cm;
  • Final separation: \rm 90\; cm = 0.90\; cm.

Apply Coulomb's law:

Initial potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.20}\\&= \rm -1.2586\; J\end{aligned}.

Final potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.90}\\&= \rm -0.279689\; J\end{aligned}.

The final potential energy is less negative than the initial one. In other words, the two particles gain energy in this process. The energy difference (final minus initial) will be equal to the work required to move them at a constant speed.

\begin{aligned}\text{Work required} &= \text{Final EPE} - \text{Initial EPE}\\&= \rm  -0.279689\; J - (-1.2586\; J)\\&\approx 0.979\; J\end{aligned}.

8 0
3 years ago
Read 2 more answers
A golfer gives a ball a maximum initial speed of 51.5 m/s. how far does it go
nata0808 [166]

<u>Answer:</u>

Golf ball will go a maximum of 270.36 meter.

<u>Explanation:</u>

  Projectile motion has two types of motion Horizontal and Vertical motion.

 Vertical motion:

          We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

          Considering upward vertical motion of projectile.

          In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g m/s^2 and final velocity = 0 m/s.

         0 = u sin θ - gt

          t = u sin θ/g

     Total time for vertical motion is two times time taken for upward vertical motion of projectile.

     So total travel time of projectile = 2u sin θ/g

Horizontal motion:

   We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

   In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 m/s^2 and time taken = 2u sin θ /g

  So range of projectile,  R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}

  Now in the given problem

     A golfer gives a ball a maximum initial speed of 51.5 m/s. how far does it go

     u = 51.5 m/s, for maximum range θ = 45⁰

   So maximum distance reached = \frac{51.5^2sin(2*45)}{9.81}=270.36 meter

So it will go a maximum of 270.36 meter.

5 0
4 years ago
What are the variables in Gay-Lussac's law? pressure and volume pressure, temperature, and volume pressure and temperature volum
Yanka [14]

Answer:

pressure and temperature (assuming volume is constant)

Explanation:

3 0
3 years ago
Read 2 more answers
As gravity continues to crush the inner core, the fusion of carbon and oxygen begins. What temperature is needed for the fusion
Olin [163]

Answer:

600,000,000 degree C

Explanation:

This stage is the last stage and is refereed to as supernova. In the beginning of this stage, gravity pulls the inner core and crush it, due to which fusion of atoms starts. Carbon and Oxygen fuse together and the temperature is about of 600,000,000 degree C.

The most heavier atom that can be formed out of this fusion is the iron. The moment all the atoms becomes of iron, no further fusion is possible hence that body emits radiation of high intensity and collapse causing a big supernova.

8 0
3 years ago
A lab cart is loaded with different masses and moved at various velocities
Sedaia [141]
A lab cart is loaded with different masses and moved at various constant velocities? the anser should be

1.0m/s → 4kg
6 0
3 years ago
Other questions:
  • Which apple has the greatest potential energy?
    5·2 answers
  • Explain why liquids flow but solids do not.
    10·2 answers
  • A fluid exerts pressure due to its DENSITY right??(As one of the factors,There are other factors too)
    6·1 answer
  • The level of closeness between a measured quantity and the actual or standard value is called what?
    6·2 answers
  • What amount of heat is removed to lower the temperature of 80 grams of water from 75ºC to 45ºC? The specific heat of liquid wate
    12·2 answers
  • 4. When an ice cube in a glass of water melts, does the water level in the glass
    8·1 answer
  • An underlying theme of astronomy is that the...
    12·1 answer
  • A person riding a bike has an initial velocity of 2.5 m/s and accelerates at a rate of 1.5 m/s2 for
    14·1 answer
  • An eraser is tied to a string swung in a horizontal circle. Identify the type of force which causes this object to travel along
    9·1 answer
  • Say you were at mission control on
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!