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elena-s [515]
3 years ago
11

Two equipotential surfaces surround a +2.90 x 10-8-C point charge. How far is the 220-V surface from the 85.0-V surface?

Physics
1 answer:
RUDIKE [14]3 years ago
4 0
The potential difference isV=220−85=135.
Now the potential V at distance d from a point charge Q isV=Q/4πϵ0d
If you solve this for d and plug in the potential difference you will get the answer.
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The basketball coach tells his team to run sprints back and forth across the court, which is 30 m long. They start at the left e
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5 0
3 years ago
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notka56 [123]

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s        

Explanation:

Given data,

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Using the III equation of motion,

                          v² = u² + 2gs

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Substituting the values,

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Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s        

4 0
3 years ago
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