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ra1l [238]
3 years ago
9

A commonly used unit of mass in the English system is the pound-mass, abbreviated lbm, where 1 lbm = 0.454 kg. What is the densi

ty of glycerine in pound-mass per cubic foot? (Assume the density of glycerine is 1.26 ✕ 103 kg/m3.)
Physics
1 answer:
Gemiola [76]3 years ago
3 0

Answer: The density of glycerine will be 0.028lbm/foot^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given:

Density of glycerine= 1.26\times 10^3kg/m^3

1 lbm = 0.454 kg

1 kg =\frac{1}{0.454}=2.2lbm

Thus 0.454kg=\frac{2.2}{1}\times 0.454=0.99

Also 1m^3=35.3147foot^3

Putting in the values we get:

Density=\frac{0.99lbm}{35.3147}=0.028lbm/foot^3

Thus density of glycerine will be 0.028lbm/foot^3

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A total of 25.6 kJ of heat energy is added to a 5.46 L sample of helium at 0.991 atm. The gas is allowed to expand against a fix
bagirrra123 [75]

Answer:

(a) W = 1329.5 J = 1.33 KJ

(b) ΔU = 24.27 KJ

Explanation:

(a)

Work done by the gas can be found by the following formula:

W = P\Delta V

where,

W = Work = ?

P = constant pressure = (0.991 atm)(\frac{101325\ Pa}{1\ atm}) = 100413 Pa

ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)(\frac{0.001\ m^3}{1\ L}) = 0.01324 m³

Therefore,

W = (100413 Pa)(0.01324 m³)

<u>W = 1329.5 J = 1.33 KJ</u>

<u></u>

(b)

Using the first law of thermodynamics:

ΔU = ΔQ - W (negative W for the work done by the system)

where,

ΔU = change in internal energy of the gas = ?

ΔQ = heat added to the system = 25.6 KJ

Therefore,

ΔU = 25.6 KJ - 1.33 KJ

<u>ΔU = 24.27 KJ</u>

3 0
3 years ago
Determina la velocidad de un avión que recorre 459 km en 67 min
satela [25.4K]

Answer:

122397.7

Explanation:

4 0
2 years ago
A car achieves a velocity 50 meters per second after 5 seconds. What is the Car's acceleration?
Reptile [31]

Answer: 10 m/s

Explanation: Velocity/Time

50/5= 10

:)

7 0
3 years ago
Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz
Katen [24]

Answer:

The velocity is v  =  6.66 \  m/s

Henrietta is at distance s=  18.17 \  m from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is v=  2.70 \ m/s

The height of the window from the ground is h  =  36.5 \  m

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

t  =  \sqrt{\frac{2 *  h }{g} }

=> t  =  \sqrt{\frac{2 *  36.5 }{9,8} }

=> t  =  2.73 \  s

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

T =  t +  t_1

Here t_1 is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

T = 2.73  +  4

=> T = 6.73 \  s

Generally the distance covered by Henrietta before catching her lunch is

s=  v  *  T

=> s=  2.70  * 6.73

=> s=  18.17 \  m

Generally the speed with which Bruce threw her lunch is mathematically represented as

v  =  \frac{18.17}{2.73}

v  =  6.66 \  m/s

4 0
3 years ago
what is the mass of an object that needs a force of 6600N to increase its speed from rest to 107 m/s in 2.3 seconds
Ray Of Light [21]
To answer this question do you need to know the formula to get the rate of change of acceleration (a=Δv/Δt; Δv= final velocity - initial velocity) and the formula to find the force of an object given a constant acceleration (F=m*a). Given these two formulas you can applicate them to solve for the mass of an object.

6 0
3 years ago
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