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4 years ago

Please help me I'm I need the answers

Mathematics

1 answer:

Neporo4naja [7]4 years ago

8 0

#1: 0.35
#2: 75%
#3: s = 4
#4: 0.08 is greater
#5: 15
#6: t = 20
#7: 2 7/10
#8: 100.06
#9: 0

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A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f

sergey [27]

We need radius

Let that be r

πr²=452.16
3.14r²=452.16
r²=144
r=√144
r=12ft

6 0

2 years ago

Read 2 more answers

What two numbers can add to 4 but multiple to -12

olasank [31]

Answer:

Numbers: 6 and -2

Step-by-step explanation:

Equations

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

$x+y=4\qquad\qquad [1]$

$x.y=-12\qquad\qquad [2]$

Solving [1] for y:

$y=4-x$

Substituting in [2]

$x(4-x)=-12$

Operating:

$4x-x^2=-12$

Rearranging:

$x^2-4x-12=0$

Solving with the quadratic formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

With a=1, b=-4, c=-12:

$\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}$

$\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}$

$\displaystyle x=\frac{4\pm 8}{2}$

The solutions are:

$\displaystyle x=\frac{4+ 8}{2}=6$

$\displaystyle x=\frac{4- 8}{2}=-2$

This confirms the preliminary results.

Numbers: 6 and -2

7 0

3 years ago

Help its math again i forgot how to do it theres 2

Scilla [17]

Answer:

first is 6/8 and second is 7/8

Step-by-step explanation:

5 0

3 years ago

A square has sides with lengths of (x - 2) units. A rectangle has a length of x units and a width of

vagabundo [1.1K]

Answer:

(A)The area of the square is greater than the area of the rectangle.

(C)The value of x must be greater than 4

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

Step-by-step explanation:

The Square has side lengths of (x - 2) units.

Area of the Square

$(x-2)^2=(x-2)(x-2)=x^2-2x-2x+4\\=(x^2-4x+4) \:Square \:Units$

The rectangle has a length of x units and a width of (x - 4) units.

Area of the Rectangle = $x(x-4)=(x^2-4x) \:Square \:Units$

The following statements are true:

(A)The area of the square is greater than the area of the rectangle.

This is because the area of the square is an addition of 4 to the area of the rectangle.

(C)The value of x must be greater than 4

If x is less than or equal to 4, the area of the rectangle will be negative or zero.

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

3 0

3 years ago

This one a little weird

Ludmilka [50]

Answer:

It might be 10 but tell me if I'm right or wrong

Step-by-step explanation:

6 0

3 years ago