Please help me I'm I need the answers

Mathematics

1 answer:

Neporo4naja [7]4 years ago

8 0

#1: 0.35
#2: 75%
#3: s = 4
#4: 0.08 is greater
#5: 15
#6: t = 20
#7: 2 7/10
#8: 100.06
#9: 0

You might be interested in

if the markup formula is 40percent of cost and the selling price is 49.99what is the cost/ a 31.76 b 33.33 c 34.33 d 35.71

NNADVOKAT [17]

An item, x, is marked up 40% and now costs $49.99
40% is 0.40
1 times any number will be the same number so we'll use that to add on the original price to the amount of increase
(1+0.40)x=49.99
x=49.99/1.4
x=35.71 so D is the answer

6 0

3 years ago

Please help!

Nimfa-mama [501]

Answer:

As "x" increases "y" *decreases*

y as a function of x is not *constant*

Therefore the function is *nonlinear*

For all values of x, the function value y *≥* 0.

The y intercept of the graph is *8*

x=1 function value of y is *5*

7 0

3 years ago

Janet has $120. If she saves $20 per week, in how many days will she have $500

Burka [1]

<span>Divide $380 by 20 and then multiply the result by 7. Its really not hard I promise I basically just gave you the answer</span>

4 0

3 years ago

Read 2 more answers

A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH

Burka [1]

Two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH : <u>rotation -90° and translation (0,2)</u>

<h3>Further explanation</h3>

There are several forms of transformation, including translation, dilation, rotation or reflection

There are 2 shapes of geometry:

Similar figures:

the same shape but different in size,

Congruent figures:

the same size and the same shape

Both polygons will appear congruent if, after being transformed, the two polygons will map exactly to each other

A sequence of two transformations e can do is :

1. rotation -90°

Let point H(4,1) from polygon GFJIH , we rotate -90°

$\left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4-6\\1+1\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}-2\\2\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}8\\1\end{array}\right]$