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vaieri [72.5K]
3 years ago
14

Calculate the midpoint between (2,-5) and (4, -7).

Mathematics
1 answer:
balandron [24]3 years ago
5 0

The midpoint between (2,-5) and (4, -7)  is Option D.(3-6)

Step-by-step explanation:

Given:

Points (2,-5) and (4, -7)

To Find:

Midpoint of the points=?

Solution:

The midpoint that lies between the two points is given by

(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Where

(x_m, y_m)= coordinates of the midpoint

(x_1, y_1)= coordinates of the first point

(x_2, y_2)= coordinates of the second point

we have,

x_1= 2

y_1= -5

x_2= 4

y_2= -5

Substituting the values in the mid point formula,

(x,y)=(\frac{(2+4)}{2},\frac{(-5-7)}{2})

(x,y)=(\frac{(6)}{2},\frac{(-12)}{2})

(x,y)=(3,-6)

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The image of point (−3, 5) under translation T is (6, -8). What is the image of point (4, 7) under the same translation?
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Answer:

(13,-6)

Step-by-step explanation:

If you are at (-3,5) and you translate T to give you (6,-8), that means you translated (9,-13) because you moved right 9 units in the positive x direction and down 13 units in the negative y direction.

Apply this translation T to (4,7) and you get (13,-6).

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I NEED HELP WILL GIVE BRAINLIEST!! PLEASE HELP ME ASAP!!!!
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Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

∴ hypotenuse = \sqrt{73} = 8.544003745

- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

3 0
3 years ago
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