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3 years ago

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At midnight,the temperature in Alto is -3.8°C.The wind chill makes the temperature feel 5.6°C colder than the actual tamperature

.What is the wind-chill tempeture?

2 answers:

Anuta_ua [19.1K]3 years ago

5 0

To solve this question you will need to subtract -3.8 by 5.6 which is equal to -9.4. So the final answer is -9.4°C

Sav [38]3 years ago

4 0

Answer:

-3.8 by 5.6 which is equal to -9.4. So the final answer is -9.4°C

Step-by-step explanation:

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What are the constant terms in the expression?<br> 8m−5n+2+m−14

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The constant terms are: -14, and +2

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The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

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3 years ago

URGENT PLEASE HELP<br> x/240 = 82/100 what is X?

Zielflug [23.3K]

x/240 = 82/100

240 : 100 = 2.4

so 240 is divided with 2,4 giving 100, this will work with 82 too. So, 82 × 2.4 = 196,8

Answer : x = 196,8

prove :

196,8/240 = 82/100 = 41/50

see the picture

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3 years ago

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Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

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4 years ago

HOW DO YOU FIND THIS AGAIN PLS HELP!

strojnjashka [21]

<h2>28 units²</h2><h2>____________________</h2>

<u>Step-by-step explanation:</u>

length = 8 units

breadth = 3.5 units

area = length × breadth

= 8 × 3.5

= 28 units²

<h2>____________________</h2><h2>FOLLOW ME</h2>

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