Answer:
Magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
Explanation:
Given;
number of turns of solenoid, N = 269 turn
length of the solenoid, L = 102 cm = 1.02 m
radius of the solenoid, r = 2.3 cm = 0.023 m
current in the solenoid, I = 3.9 A
Magnitude of the magnetic field inside the solenoid near its centre is calculated as;
![B = \frac{\mu_o NI}{l} \\\\](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu_o%20NI%7D%7Bl%7D%20%5C%5C%5C%5C)
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
![B = \frac{4\pi*10^{-7} *269*3.9}{1.02} \\\\B = 1.293 *10^{-3} \ T](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B4%5Cpi%2A10%5E%7B-7%7D%20%2A269%2A3.9%7D%7B1.02%7D%20%5C%5C%5C%5CB%20%3D%201.293%20%2A10%5E%7B-3%7D%20%5C%20T)
Therefore, magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
<h2><u>Question</u><u>:</u><u>-</u></h2>
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?
<h2><u>Answer:</u><u>-</u></h2>
<h3>Given,</h3>
=> Force applied by Ryan = 10N
=> Distance covered by the book after applying force = 30 cm
<h3>And,</h3>
30 cm = 0.3 m (distance)
<h3>So,</h3>
=> Work done = Force × Distance
=> 10 × 0.3
=> 3 Joules
![\small \boxed{work \: done \: by \: Ryan \: = 3 \: Joules}](https://tex.z-dn.net/?f=%20%5Csmall%20%5Cboxed%7Bwork%20%5C%3A%20done%20%5C%3A%20%20by%20%5C%3A%20Ryan%20%5C%3A%20%20%3D%203%20%5C%3A%20Joules%7D)
Answer:
= 391.67 Hz
Explanation:
The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency (
).
The For a vibrating string, the fundamental frequency (
) can be determined by:
= ![\frac{v}{2L}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7B2L%7D)
Where v is the speed of waves of the string, and L is the length of the string.
L = 42.0 cm = 0.42 m
v = 329 m/s
= ![\frac{329}{2*0.42}](https://tex.z-dn.net/?f=%5Cfrac%7B329%7D%7B2%2A0.42%7D)
= ![\frac{329}{0.84}](https://tex.z-dn.net/?f=%5Cfrac%7B329%7D%7B0.84%7D)
= 391.6667 Hz
The fundamental frequency of the string is 391.67 Hz.
Answer:
The Ring of Fire
Explanation:
The ring of fire is also called the Circum-Pacific Belt, it is a path along the pacific ocean consisting of active volcanoes and frequent earthquakes.
It has a length of approximately 40,000 kilometers. It lies on the edge of tectonic plates where the in-earth vibrations and geothermal energies are prone to erupt out.
Ring of fire inhibits about 75% o the earth's volcanoes and 95% of earthquakes occur in this region.