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aliina [53]
3 years ago
9

Two metal spheres are hanging from nylon threads. When you bring the spheres close to each other, they tend to attract. Based on

this information alone, discuss all the possible ways that the spheres could be charged. Is it possible that after the spheres touch, they will cling together? Explain.
Physics
1 answer:
Tamiku [17]3 years ago
4 0

Explanation:

In the given question, the two metal spheres were hanged with the nylon thread.

When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.

The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.

During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.

It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.

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How long will it take to go 150000m traveling at 50km/hr
Tom [10]

Answer:

3000 hurs

Explanation:  just divide 150000 by 50 and get 3000

4 0
3 years ago
Determine the components of reaction at the fixed support
denis-greek [22]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The components of reaction at the fixed support are  

    A_{(x)}  = 400  \ N ,  A_{(y)}  = -500  \ N ,  A_{(z)}  = 600  \ N ,  M_x  = 1225 \  N\cdot m , M_y  = 750 \  N\cdot m ,  M_z  = 0 \  N\cdot m

Explanation:

Looking at  the diagram uploaded we see that there are two  forces acting along the x-axis on the fixed support    

   These force are  400 N  and  A_{(x)} [ i.e the reactive force of  400 N  ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(x)}  - 400  = 0

=>     A_{(x)}  = 400  \ N

Looking at  the diagram uploaded we see that there are two  forces acting along the y-axis on the fixed support  

   These force are  500 N  and  A_{(y)} [ i.e the force acting along the same direction with 500 N   ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(y)}  + 500  = 0

=>     A_{(y)}  = -500  \ N

Looking at  the diagram uploaded we see that there are two  forces acting along the z-axis on the fixed support  

       These force are  600 N  and  A_{(z)} [ i.e the reactive force of  600 N  ]

Hence the sum of forces along the x axis is mathematically represented as

        A_{(z)}  - 600  = 0

=>     A_{(z)}  = 600  \ N

Generally taking moment about A along the x-axis we have that

    \sum M_x  = M_x  - 500 (0.75 + 0.5) + 600 ( 1 ) = 0

=>   M_x  = 1225 \  N\cdot m

Generally taking moment about A along the y-axis we have that

    \sum M_y  = M_y  - 400 (0.75 ) + 600 ( 0.75 ) = 0

=>   M_y  = 750 \  N\cdot m

Generally taking moment about A along the z-axis we have that

    \sum M_z  = M_z = 0

=>   M_z  = 0 \  N\cdot m

8 0
3 years ago
Phineas and Ferb are riding their bikes on Main Street. They begin at 11 Mile Rd at
Lady bird [3.3K]

Answer:

1 hour and 25 minutes

Explanation:

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7 0
2 years ago
A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N
mart [117]

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force(F_{A}) and the kinetic frictional force(F_{R}). i.e

F = F_{A} - F_{R}    -----------------(i)

Note that;

F_{R} = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = F_{A} - μmg        -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

F_{A} = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

3 0
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Luba_88 [7]
I don’t know español
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