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Airida [17]
3 years ago
11

At which life cycle stage are stars most stable

Physics
2 answers:
malfutka [58]3 years ago
8 0
The answer is the Young star stage. Hope this helps!
asambeis [7]3 years ago
4 0
~Hello there!

Your question: At which life cycle stage are stars most stable?

Your answer: The young star stage is the life cycle where the stars are most stable because the stars are just flaming, no interference nor there is no disturbance.

Any queries ^?

Happy Studying! 
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The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh
frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

y\propto x^{1.25}

y=kx^{1.25}

k=\dfrac{y}{x^{1.25}}

Put the value into the formula

k=\dfrac{1.8}{1.1^{1.25}}

k=1.5978

We need to calculate the crab weight

y=kx^{1.25}

Here, x = 0.85 g

Put the value into the formula

y=1.5978\times(0.85)^{1.25}

y=1.3040\ gram

Hence, The weight of body is 1.3040 gram.

7 0
4 years ago
An airplane in the earth’s magnetic field can develop a voltage between its wingtips.
Svetradugi [14.3K]

Answer:

emf=0.125\ V

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

Explanation:

Given:

  • velocity of plane, v=250\ m.s^{-1}
  • magnetic field, B=5\times 10^{-5}\ T
  • angle between velocity and magnetic field, \theta=30^{\circ}
  • span of the wing, l=20\ m

We know:

emf=B.l.v\ sin\theta

emf=5\times 10^{-5}\times 20\times 250\times sin30^{\circ}

emf=0.125\ V

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

7 0
3 years ago
An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0
Delicious77 [7]

Answer: y(t)= 1/π^2 sin(6*π^2*t)

Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:

y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.

The data are: ν= 3π; y(t=0)=0 and y'(0)=6.

Firstly we know that 2πν=ω then ω=6*π^2

Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0

Besides y'(t)=6*π^2*A*cos (6*π^2*t)

y'(0)=6=6*π^2*A*cos (6*π^2*0)

6=6*π^2*A then A= 1/π^2

Finally the equation is:

y(t)= 1/π^2 sin(6*π^2*t)

3 0
3 years ago
Read 2 more answers
A boy whirls a ball on a string in a horizontal circle of radius 0.65 m. If the ball is traveling at 9 m/s, what is the centripe
djverab [1.8K]

Answer:

ac = 124.6 m/s²

Explanation:

When an object executes a uniform circular motion, acceleration is produced in it due to a change in its direction during the motion. This acceleration is called the centripetal acceleration. The formula used to find this acceleration is given as follows:

a_{c} = \frac{v^{2}}{r}\\

where,

ac = centripetal acceleration = ?

v = speed = 9 m/s

r = radius = 0.65 m

Therefore,

a_{c} = \frac{(9\ m/s)^{2}}{0.65\ m}\\

<u>ac = 124.6 m/s²</u>

5 0
3 years ago
find the distance traveled in km when the average speed is 60 km per hour and the time taken is 3 and 1/2 hours​
Anna35 [415]

Answer:

210 km

Explanation:

60 x 3  1/2 = 210

3 0
3 years ago
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