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3 years ago

How can you tell that this paragraph uses a quotation? Check all that apply?

1 answer:

8 0

Answer- There are two reasons that we know quotations have been used first is the use of of name of the person who quoted it and secondly the quotation is written inside the quotation marks.

Explanation- Quotation is nothing but using a line that has been already quoted by someone somewhere. Such sentences are normally written inside quotation marks. In the above given paragraph the name of the person who quotes the sentence is also given hence we know that our quotation has been used.

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when an apple falls towards the earth the earth moves up to meet the apple. Is it true? If yes, why is the earth motion not noti

timurjin [86]

Answer:

Explanation:

The apple also exerts an equal and opposite force on the earth but earth does not move because the mass of apple is very small,due to which the gravitational force produces a large acceleration in it (a=F/m) and we can see the apple falling towards the earth but the mass of earth is very large,the same gravitational .

3 0

3 years ago

I need help fast!!!

Fantom [35]

You could easily help yourSELF if you simply follow the instructions in the question and "Use Ohm's law" to calculate the resistance.

Ohm's Law: Resistance = (voltage) / (current)

Resistance = (10 v) / (5 A)

<em>Resistance = 2 ohms</em>

8 0

3 years ago

¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!

asambeis [7]

Answer:

(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

Explanation:

(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J

The electric potential is given by

W = q V

$40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V$

(b)

charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m

Let the potential is V.

$V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V$

(c)

Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V

Let the charge is q.

W= q V

$8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C$

3 0

3 years ago

An object, initially at rest moves 250m in 17s. What is it's acceleration?

Gekata [30.6K]

With the values you've given, only velocity can be found.
Acceleration is rate of change of velocity

d= 250s
t= 17s

a= d/t
= $\frac{250}{17}$
= 4.7 $\frac{m}{s}$

8 0

3 years ago

What is the insertion for the brachialis

Alona [7]

Coronoid process of the ulna

6 0

3 years ago