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Strike441 [17]
2 years ago
7

Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2

column table with 4 rows. The first column is labeled spring with entries W, X, Y, Z. The second column is labeled spring constant in newtons per meter with entries 24, 35, 22, 15. Which lists the springs based on the amount of elastic potential energy, from greatest to least?
Physics
1 answer:
RoseWind [281]2 years ago
4 0

Answer:

X,W,Y,Z

Explanation:

It is what it is. and i took the edge test

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You blow across the open mouth of a test tube and produce the fundamental standing wave of the air column inside the test tube i
WITCHER [35]

Answer:

B: 980 Hz

Explanation:

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3 years ago
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Carlos was camping and getting cold as the sun went down. He wanted to light a fire for warmth and light. However, he discovered
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1. The chemical reaction produced by Carlo's fire is exergonic because energy is "going out". As the reaction proceeds, entropy increases as the energy stored in the dry wood and leaves are used up as fuel to create the fire which produces low quality light and warmth.  

2. This reaction is a classic example of an exothermic reaction. Exothermic reactions are characterized with the presence of heat and light in the products. Combustion reactions are always exothermic in nature.

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6 0
3 years ago
How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest<br> to 51 m/s?
Nesterboy [21]

Answer:

 t  = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity  = 0m/s

Final velocity  = 51m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

        Acceleration  = \frac{v  - u }{t}  

v is the final velocity

u is the initial velocity

t is the time taken

  So;

       3.1  = \frac{51 - 0}{t}  

    3.1t  = 51

       t  = 16.5s

8 0
3 years ago
Consider a uniform hoop of radius r and mass m rolling without slipping. which is larger, its translational kinetic energy or it
OlgaM077 [116]
<span>translational kinetic energy is larger than its rotational kinetic energy</span>
3 0
3 years ago
The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 m
kramer

Answer:

The focal length of eyepiece is 3.68 cm.

Explanation:

Given that,

Distance = 19 cm

Focal length = 5.5 mm

Magnification = 200

Object distance = -25 cm

We need to calculate the focal length

Using formula of magnification

m=\dfrac{d}{f_{o}}+\dfrac{-25}{f_{0}f_{e}}

Put the value into the formula

f_{e}=\dfrac{19\times(-25)}{.55(-200-\dfrac{19}{.55})}

f_{e}=3.68\ cm

Hence, The focal length of eyepiece is 3.68 cm.

3 0
3 years ago
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