Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2
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Answer:
Explanation:
Given
radius of circle=1.4 m
Height of stone above ground=1.5 m
Horizontal distance(R)=10 m
It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground
t=0.55 s
Initial horizontal velocity at the time of break is given by u
u=18.07 m/s
Therefore magnitude of centripetal acceleration is given by