The angle of bank needed, measured from the vertical is 86.6⁰.
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Banking angle of the circular path</h3>
The angle of bank needed, measured from the vertical is calculated as follows;
v = √(rg tanθ)
where;
- v is the speed = 1440 km/h = 400 m/s
- r is radius of the curve = 960 m
- g is acceleration due to gravity
- θ is the banking angle
400² = (960 x 9.8 x tanθ)
tanθ = 400²(960 x 9.8)
tanθ = 17
θ = arc tan(17)
θ = 86.6⁰
Thus, the angle of bank needed, measured from the vertical is 86.6⁰.
Learn more about banking angle here: brainly.com/question/8169892
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solid to gas or gas to liquid
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Check the attachment for solution
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Answer:
1- For the track B. The potential energy is the same for the two cars, but because of the slope of the track, the car B earn kinetic energy faster. The gravitation acceleration of the cars will be g•sinθ, and the angle of the track B will have a bigger value for sinθ
2- The conservation of energy applies because the roller coaster is a closed track. When a car climb the track, it earn GPE, which is given by mgh, when it get down in the track, it transform GPE in KE, which is given in 1/2mv².
3-
Position of car (m) GPE KE GPE + KE
top (30m) 60000 0 60000
bottom (0m) 0 60000 60000
halfway down (15m) 30000 30000 60000
three-quarters way down 15000 45000 60000