Question

1. (I) If the magnetic field in a traveling EM wave has a peak magnitude of 17.5 nT at a given point, what is the peak magnitude of the electric field

Answer 1

Answer:

The electric field is $E = 5.25 V/m$

Explanation:

From the question we are told that

    The peak magnitude of the magnetic field is  $B = 17.5 nT = 17.5 *10^{-9}\ T$

Generally the peak magnitude of the electric field is mathematically represented as

         $E = c * B$

Where c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

So

       $E = 3.0 *10^{8} * 17.5 *10^{-9}$

       $E = 5.25 V/m$