Answer:
A general solution is 
and a particualr case is mgh, it is just to distance around the radius Earth.
Explanation:
We can use a general equation of the potential energy to understand the particular and general case:
The potential energy is defined as 
, we know that the gravitational force is 
, so we could find the potential energy taking the integral of F.
(1)
We can find the particular case, just finding the gravitational potential energy difference:
. Here Uf is the potential evaluated in r+Δh and Ui is the potential evaluated in r.
Using (1) we can calculate ΔU.
Simplifying and combining terms we have a simplified expression.
(2)
Let's call 
. It is the acceleration due to gravity on the Earth's surface, if r is the radius of Earth and M is the mass of the Earth and we can write (2) as ΔU=mgh, but if we have distance grader than r we should use (2), otherwise, we could get incorrect values of potential energy.
I hope i hleps you!
Electrons have electrical magnetic fields that require them to have energy that is too intense for quarks
Spherical because it’s more like clouds
The kinetic energy will rise once the body comes back down. As it goes up, the potential energy increases while the kinetic energy decreases. Once the body is at its maximum height, the potential energy is at it’s highest. When it starts falling, it will gain kinetic energy and lose potential energy.
Infrared light because it is barely able to be seen
