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yanalaym [24]
3 years ago
15

Please i need help it is due at 9

Mathematics
2 answers:
shutvik [7]3 years ago
8 0
I think the answer is letter c
zhenek [66]3 years ago
6 0

Answer:

I believe the answer is C

Step-by-step explanation:

Here's why:

83 are in service.

69 out of the 83 have a working radio.

The percentage of buses ready for service that have a working radio is therefore 69/83 = .831325301 * 100% = 83.1325301%.

You might be interested in
How to find increase percent from 44 to 48
lesantik [10]
9.09% increase.

First find the difference between the two numbers.

(4)

then, divide the result by the original amount...

4÷ 44

then multiply by 100

9.09 and that is to the nearest 10th otherwise your answer 9% increase from 44 to 48.
3 0
3 years ago
If f(x) = 2x + 3 and g(x) = x^2 + 1,find f(g(3)).<br> A.) 23<br> B.) 47<br> C.) 82<br> D.) 90
marta [7]
The answer is A). 23. 
<span>g(x)= 2x + 3 </span>
<span>g(x) = x^2 + 1 </span>
<span>g(3) = 10 </span>
<span>f(g(3)) </span>
<span>= f(10) </span>
<span>= 23 </span>
6 0
4 years ago
Can somebody help me with this. Will mark brainliest.
Monica [59]

Answer:

15.9

Step-by-step explanation:

3 0
3 years ago
A chemist has two alloys, one of which is 15% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of
vlabodo [156]

Answer: 490 grams of the first alloy should be used.

30 grams of the second alloy should be used.

Step-by-step explanation:

Let x represent the weight of the first alloy in grams that should be used.

Let y represent the weight of the second alloy in grams that should be used.

A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is

0.15x and 0.2x

The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is

0.3y and 0.5y

If the alloy to be made contains 82.5 g of gold, it means that

0.15x + 0.3y = 82.5 - - - - - - - - - - - -1

The second alloy would also contain 113 g of lead. This means that

0.2x + 0.5y = 113 - - - - - - - - - - - - -2

Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes

0.03x + 0.06y = 16.5

0.03x + 0.075y = 16.95

Subtracting, it becomes

- 0.015y = - 0.45

y = - 0.45/- 0.015

y = 30

Substituting y = 30 into equation 1, it becomes

0.15x + 0.3 × 30 = 82.5

0.15x + 9 = 82.5

0.15x = 82.5 - 9 = 73.5

x = 73.5/0.15

x = 490

6 0
3 years ago
If you set aside $9000 at the end of each year for the next 22 years in a Roth IRA, how much will you have at your retirement 22
madam [21]

Answer:

$501,049.37

Step-by-step explanation:

For computing the amount after 22 years we need to applied the future value which is shown in the attachment below:

Given that

PMT = $9,000

NPER = 22 years  

Annual rate = 0.078

Quarterly= 0.078 ÷ 4 = 0.0195

Effective annual rate = (1.0195^4) - 1 = 0.0803113041

Now applied the formula which is given below

= -FV(RATE;NPER;PMT;PV)

After applying the above formula, the future value is $501,049.37

7 0
3 years ago
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