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dybincka [34]
3 years ago
12

How many moles of Boron are present in 20g of borax (sodium tetraborate)?​

Chemistry
1 answer:
stira [4]3 years ago
5 0
20 grams of borax contains (20.0g) / (201 g mol -1) =0.10 mol of borax.

Therefore 0.40 mol of borax
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Which <br> molecule has the same shape and hybridization as methane
Korvikt [17]
Hi, the answer is <span>CF2Cl2 :)</span>
6 0
4 years ago
Sulfur has an atomic mass of 32 u and Avogadro's number is 6 × 1023 formula units/mole. The number of sulfur atoms in 1 g of sul
Vikki [24]

Answer:

The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6\times 10^{23}

Given atomic mass of sulfur = 32 u

Which means that:-

32 g of sulfur contains 6\times 10^{23} of atoms

Also,

1 g of sulfur contains \frac {6\times 10^{23}}{32} of atoms

<u>So, The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms</u>

6 0
3 years ago
Question 6: The Ideal Gas Law (7 points) a. What is the mathematical equation for the ideal gas law? Identify each variable and
azamat

The mathematical equation for the ideal gas law is PV = nRT.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

(A)

PV = nRT

The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

(B)

Where the pressure - P, is in atmospheres (atm) the volume - V, is in liters (L) the moles -n, are in moles (m) and Temperature -T is in Kelvin (K) as in all gas law calculations.

(C)

A. Boyle's law

B. Charles's law

C. Avogadro's law

D. Dalton's law

____ - P_1V_1 = P_2 V_2

____ \frac{V}{T} = k

____ \frac{V_1}{T_1} = \frac{V_2}{T_2}

____ V = kn

____ PV = k

____- P total = P_1 + P_2 + P_3 + ...

<u>Boyle's</u><u> law</u> - P_1V_1 = P_2 V_2

<u>Charles's</u><u> law</u> - \frac{V}{T} = K

<u>Charles's law</u> - \frac{V_1}{T_1} = \frac{V_2}{T_2}

<u>Avogadro's law</u>- V = kn

<u>Boyle's law</u> - PV = k

<u>Dalton's law</u><u> </u>- P total = P_1 + P_2 + P_3 + ...

Learn more about the  ideal gas law here:

brainly.com/question/21353806

#SPJ1

6 0
2 years ago
The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this t
vazorg [7]

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

The value of standard Gibbs free energy is 0 for equilibrium reactions.

To calculate \Delta S^o_{vap} for the reaction, we use the equation:

\Delta S^o_{vap}=\frac{\Delta H^o_{vap}}{T}

where,

\Delta S^o_{vap} = standard entropy change of vaporization

\Delta H^o_{vap} = standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol    (Conversion factor: 1 kJ = 1000 J)

T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

\Delta S^o_{vap}=\frac{30700J/mol}{353.3K}=86.9J/(mol.K)

Hence, the correct answer is Option c.

8 0
3 years ago
An electron has an uncertainty in its position of 471 pm .
olya-2409 [2.1K]

<u>Answer:</u>

$\Delta x . \Delta p \geq \frac{h}{4 \pi}$

∆x is the Uncertainty in the position of the particle

∆p is the Uncertainty in the momentum of the particle

$\Delta p=\frac{h}{4 \pi \times m \times \Delta x}$

$=\frac{6.626 \times 10^{-34} \mathrm{kgm}^{2} s^{-1}}{4 \times 3.14 \times 9.109 \times 10^{-31} \mathrm{kg} \times 471 \times 10^{-12} \mathrm{m}}$

$=\frac{6.626 \times 10^{-34} \mathrm{ms}^{-1}}{53887 \times 10^{-43}}$

=1.23\times10^5 ms^{-1} is the answer

3 0
3 years ago
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