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Eva8 [605]
3 years ago
15

The survival of aquatic organisms depends on the small amount of O2 that dissolves in H2O . The diagrams above represent possibl

e models to explain this phenomenon. Which diagram provides the better particle representation for the solubility of O2 in H2O , and why?
Chemistry
1 answer:
koban [17]3 years ago
4 0

Answer:

Diagram 1

Explanation:

The solubility of the oxygen gas in water has to do with the interaction of the oxygen with the dipoles in water.

Water is a polar molecule having oxygen as the negative dipole and hydrogen as the positive dipole.

Water can interact with the oxygen atoms in the molecule via intermolecular hydrogen bonds with molecular oxygen as shown in diagram 1.

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Answer:

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Explanation:

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7 0
3 years ago
Read 2 more answers
1. Stirring increases the rate of solution
Blababa [14]

Answer:

1) <em>The correct answer is A. Collision</em>

2) A hot solvent helps a solid dissolve faster because an increase in <u><em>kinetic energy</em></u> that also increases the rate of collisions

Explanation:

When a solute is added into a solvent and stirred, the solute particles get distributed to all parts of the solvent as a result of stirring.

More collisions occur between the solute and the solvent due to stirring. This increases the rate of dissolving.

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3 0
3 years ago
Which of the following statements is true?
k0ka [10]
The second and first one but if it isn’t 2 choices then 1
4 0
3 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0
3 years ago
Following reactions<br>FeSO4+KOH<br>​
prohojiy [21]

Explanation:

FeSO _{4} + \: KOH \: →K _{2}SO _{4} \:  +  \: Fe(OH) _{2}

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