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Ad libitum [116K]
3 years ago
14

How many Atoms are present in 155.8 grams of zirconium?

Chemistry
1 answer:
alex41 [277]3 years ago
3 0

Answer: 2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

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The kinetic-molecular theory explains the properties of the gases in terms of energy, size and motion of their particles.


The assumptions that the kinetic-moletuclar theory makes about the characteristics of gas particles are:


1. Gases are constituted by a large amount of particles (atoms or molecules) symilar to solid spherical sphers, in constant and random motion.


2. Gas particles move in straight line until collide with another particle or the walls of the vessel.


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4. Beside the already mentioned collisions with the walls of the vessels or between the particles, there is no interaction (attractive or repulsive forces) acting on the gas particles.

 

5. The collisions between gas particles or with the walls of the vessel are elastic: there is not loss of energy.


6. The average kinetic energy of the particles in a gas depends only on the absolute temperature of the gas: at a given temperatue every gas have the same average kinetic energy.


That collection of assumptions are used to explain such things as: the relation  of pressure withthe  number of particles, the relation of pressure and temperature, the relation of pressure and volume, the relation of volume and temperature, Avogadro's hypothesis (relation of volume and number of particles), Dalton's Law of partial pressures, and both effusion and difusion.

5 0
3 years ago
A higher amplitude means...?
vekshin1

Answer:

High amplitude is equivalent to loud sounds.

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Hello!

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