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Ad libitum [116K]
3 years ago
14

How many Atoms are present in 155.8 grams of zirconium?

Chemistry
1 answer:
alex41 [277]3 years ago
3 0

Answer: 2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

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2 years ago
Read 2 more answers
7. Calculate the amount of energy required heat 100.g to <br> H2O(s) changes to H2O(l) at 0°C
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Explanation:

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Unknown:

Amount of energy = ?

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