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Licemer1 [7]
2 years ago
14

If charcoal and sugar were the the main impurities present in crude acetanilide would recrystallisation from water be a good met

hod of purification explain why?
Chemistry
1 answer:
siniylev [52]2 years ago
4 0

Yes, recrystallization from water would be a viable technique of purification if crude acetanilide contained sugar and charcoal. Due to their physical insolubility, charcoal found in crude acetanilide and water will form a heterogeneous combination. Charcoal will separate during crystallization because it is insoluble in water. Sugar and the unreconstituted crude acetanilide make up the remaining portion of the combination. Crude acetanilide will crystallize in this combination and separate from the sugar and water solution. Filtration will be used to capture the crude acetanilide that has solidified. Sugar and water make a soluble solution, thus they are kept separate. This is how the charcoal and sugar combination is purified and its constituent parts are separated from crude acetanilide using the recrystallization process from water.

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).
Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas         Mole Fraction      kH mol/(L*atm)

           N_2                         7.81\times 10^{-1}         6.70\times 10^{-4}

           O_2                         2.10\times 10^{-1}        1.30\times 10^{-3}

           Ar                          9.34\times 10^{-3}        1.40\times 10^{-3}

          CO_2                        3.33\times 10^{-4}        3.50\times 10^{-2}

          CH_4                       2.00\times 10^{-6}         1.40\times 10^{-3}

          H_2                          5.00\times 10^{-7}         7.80\times 10^{-4}

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}

where,

p_A = partial pressure of hydrogen gas = ?

p_T = total pressure = 0.380 atm

\chi_A = mole fraction of hydrogen gas = 5.00\times 10^{-7}

Putting values in above equation, we get:

p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{H_2}=K_H\times p_{H_2}

where,

K_H = Henry's constant = 7.80\times 10^{-4}mol/L.atm

p_{H_2} = partial pressure of hydrogen gas = 1.9\times 10^{-7}atm

Putting values in above equation, we get:

C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

4 0
3 years ago
How do I draw energy level diagrams?
finlep [7]

Energy levels inside an atom are the specific energies that electrons can have when energy occupies specific orbitals. Electrons can be excited to higher energy levels by absorbing energy from the surroundings, an equivalent light is emitted when an electron returns from a high energy state to a lower one. Representation of this diagrammatic is known as the energy level diagram.

7 0
2 years ago
Why would a metal house not be a good idea in Florida or Alaska?
dolphi86 [110]
It wouldn’t be a good idea bc metal absorbs the weather around it. so in florida it would be too hot and in alaska it would be too cold!
3 0
3 years ago
Read 2 more answers
If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
yawa3891 [41]

The pH of the monoprotic weak acid is 2.79.

<h3>What are weak acids?</h3>

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

To learn more about weak acids, refer to the below link:

brainly.com/question/13032224

#SPJ4

5 0
2 years ago
A vessel of 120ml capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vess
Rainbow [258]

Given parameters:

Initial volume  = 120ml

Initial temperature  = 35°C

Initial pressure  = 1.2bar

Final volume  = 180ml

Final temperature  = 35°C

Unknown:

Final pressure  = ?

To solve this problem, we apply the combined gas law. The expression is given below;

          \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

Where P₁ is the initial pressure

           P₂ is the final pressure

          V₁ is the initial volume

          V₂ is the final volume

          T₁ is the initial temperature

           T₂ is the final temperature

We need to convert the parameters to standard units

take the volume to dm³;

      1000ml  = 1dm³

      120ml  = \frac{120}{1000} dm³  = 0.12dm³ = initial volume

Final volume;

      1000ml = 1dm³

      180ml  = \frac{180}{1000} dm³  = 0.18dm³

Now, the temperature;

       K  = 273 + °C

Initial temperature  = 273 + 35  = 308k

Final temperature  = 308k

We then input the parameters into the equation;

         \frac{1.2bar x 0.12 }{308}   = \frac{P_{2} x 0.18 }{308}

       Solving for P₂;

     P₂  = 0.8bar

The new pressure or final pressure in the vessel is 0.8bar

5 0
3 years ago
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