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3 years ago

Determine the oxidation state of cr in cr(so4)2.

Chemistry

2 answers:

tatiyna3 years ago

4 0

Answer: The oxidation state of chromium in the given compound is +4

Explanation:

Oxidation state is the number that is assigned to the element when it gains or looses electrons.

If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We take the oxidation state of chromium atom be 'x'.

Oxidation state of sulfate ion $(SO_4^{2-})$ = -2

Evaluating the oxidation state of chromium atom:

$x+2(-2)=0\\\\x=+4$

Hence, the oxidation state of chromium in the given compound is +4

NNADVOKAT [17]3 years ago

3 0

Answer:
SO4= is -2 each, and there are 2 of them,so 2 x -2 = -4, and Cr must be +4.

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Answer:

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Luden [163]

Answer:

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Explanation:

Pressure:

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Mathematical expression:

P = F/A

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F = force

A = area

We know that there are phases of matter solid liquid and gas.

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While in case of liquid molecules are packed and they can not move freely thus did not exert pressure like gaseous molecules.

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Properties of gases:

Molecule of gases randomly move everywhere and occupy all available space.

Gases don't have definite volume and shape and take the shape and volume of container in which it present.

Their densities are very low as compared to the liquid and solids.

Gas molecules are at long distance from each other therefore by applying pressure gases can be compressed.

The very weak inter molecular forces are present between gas molecules.

Properties of Liquid:

Liquid have definite volume but don,t have definite shape.

Their densities are high as compared to the gases but low as compared to the solids.

In liquid, molecules are close to each other and have greater inter molecular forces as compared to the gas molecules.

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Solids have definite volume and shape.

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Answer:

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Explanation:

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