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3 years ago

Determine the oxidation state of cr in cr(so4)2.

Chemistry

2 answers:

tatiyna3 years ago

4 0

<u>Answer:</u> The oxidation state of chromium in the given compound is +4

<u>Explanation:</u>

Oxidation state is the number that is assigned to the element when it gains or looses electrons.

If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We take the oxidation state of chromium atom be 'x'.

Oxidation state of sulfate ion $(SO_4^{2-})$ = -2

Evaluating the oxidation state of chromium atom:

$x+2(-2)=0\\\\x=+4$

Hence, the oxidation state of chromium in the given compound is +4

NNADVOKAT [17]3 years ago

3 0

Answer:
SO4= is -2 each, and there are 2 of them,so 2 x -2 = -4, and Cr must be +4.

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2 years ago

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Sladkaya [172]

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lyudmila [28]

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