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lions [1.4K]
3 years ago
5

Determine the oxidation state of cr in cr(so4)2.

Chemistry
2 answers:
tatiyna3 years ago
4 0

<u>Answer:</u> The oxidation state of chromium in the given compound is +4

<u>Explanation:</u>

Oxidation state is the number that is assigned to the element when it gains or looses electrons.

If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We take the oxidation state of chromium atom be 'x'.

Oxidation state of sulfate ion (SO_4^{2-}) = -2

Evaluating the oxidation state of chromium atom:

x+2(-2)=0\\\\x=+4

Hence, the oxidation state of chromium in the given compound is +4

NNADVOKAT [17]3 years ago
3 0
Answer:
SO4= is -2 each, and there are 2 of them,so 2 x -2 = -4, and Cr must be +4.
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An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
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In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

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