Question

Determine the oxidation state of cr in cr(so4)2.

Answer 1

Answer: The oxidation state of chromium in the given compound is +4

Explanation:

Oxidation state is the number that is assigned to the element when it gains or looses electrons.

If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We take the oxidation state of chromium atom be 'x'.

Oxidation state of sulfate ion $(SO_4^{2-})$ = -2

Evaluating the oxidation state of chromium atom:

$x+2(-2)=0\\\\x=+4$

Hence, the oxidation state of chromium in the given compound is +4

Answer 2

Answer:
SO4= is -2 each, and there are 2 of them,so 2 x -2 = -4, and Cr must be +4.