0.2701 moles of water were evaporated from the sample by the heating process
Mass of evaporating dish = 8.365 g
mass of dish + hydrate = 18.597 g
mass of hydrate = (mass of dish + hydrate) - mass of dish
hydrate = 18.597 - 8.365 = 10.232 g
Mass of dehydrated material = (mass of dish + dehydrate ) - mass of dish
dehydrated material = 18.735 - 8.365 = 5.37 g
Mass of water evaporated = hydrate - dehydrate
mass of water = 10.232 - 5.37 = 4.862 g
Molar mass of water = 18 gm/mol
no. of moles of water evaporated = mass / molecular mass
moles = 4.862/18 = 0.2701 moles
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