What is a solubility?

A chemistry student weighs out of sulfurous acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distill

nadezda [96]

The question is incomplete, here is the complete question:

A chemistry student weighs out 0.104 g of sulfurous acid, a diprotic acid, into a 250.0 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0700 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of NaOH needed is 36.2 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of sulfurous acid = 0.104 g

Molar mass of sulfurous acid = 82 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

$\text{Molarity of sulfurous acid}=\frac{0.104\times 1000}{82\times 250}\\\\\text{Molarity of sulfurous acid}=5.07\times 10^{-3}M$

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=5.07\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.0700M\\V_2=?mL$

Putting values in above equation, we get:

$2\times 5.07\times 10^{-3}\times 250.0=1\times 0.0700\times V_2\\\\V_2=\frac{2\times 5.07\times 10^{-3}\times 250}{1\times 0.0700}=36.2mL$

Hence, the volume of NaOH needed is 36.2 mL

5 0

3 years ago

The specific heat of aluminum is 0.214 cal/g.oC. Determine the energy, in calories, necessary to raise the temperature of a 55.5

Natasha2012 [34]

For this problem, we use the formula for sensible heat which is written below:

Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference

Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>

4 0

3 years ago

when solid pellets of sodium hydroxide (naoh) dissolve in water, the temperature of the water can rise dramatically. taking naoh

irga5000 [103]

ΔSsys and ΔSsurr both have values larger than 0.

<h3>Entropy Change: What Is It?</h3>

Entropy change is a phenomena that measures the evolution of randomness or disorder in a thermodynamic system.
It has to do with how heat or enthalpy is converted during work.
More unpredictability in a thermodynamic system indicates high entropy.
Heat transport (delta Q) divided by temperature equals the change in entropy (delta S).

<h3>What causes variations in entropy?</h3>

When a substance is divided into several pieces, entropy rises.
Because the solute particles are split apart when a solution is generated, the dissolving process increases entropy.
As the temperature rises, entropy increases.

learn more about entropy change here

brainly.com/question/6364271

#SPJ4

8 0

1 year ago

The common name for butanone, a readily available solvent, is

kobusy [5.1K]

The answer is ethyl methyl ketone.

8 0

3 years ago

Read 2 more answers

What is the product of a substitution reaction if the reactants are fluoroethane and sodium hydroxide?