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Simora [160]
2 years ago
6

What is a solubility?

Chemistry
1 answer:
kogti [31]2 years ago
6 0

Answer:the ability to be dissolved, especially in water.

Explanation:

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Describe the molecular structure of water and explain why the water molecule is polar
pentagon [3]

Explanation:

Hybridization of O in H_2O = sp^3

So, water molecule has four hybrid orbitals.

Two hybrid orbitals form 2 sigma bond with two H atoms.

Remaining two hybrid orbitals are occupied by two lone pairs.

Because of lone pair-lone pair repulsion, shape of H_2O becomes bent.

Water molecule is polar because of difference in eletronegativities of O and H.

O is more electronegative as comapared to hydrogen. So bonding electrons get attracted towards O atom which results in the development of partial negative charge on O atom and partial positive charge on H atoms.

Because of development of partial negative and partial positive charge, water molecule becomes polar.

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3 years ago
Examples of polar covalent bonds
mars1129 [50]
A water molecule, abbreviated as H2O, is an example of a polar covalent bond. The electrons are unequally shared, with the oxygen atom spending more time with electrons than the hydrogen atoms. Since electrons spend more time with the oxygen atom, it carries a partial negative charge.
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2 years ago
“Sound plays an important role in our lives”. Give two points in support of this statement.
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Sound can be used to alert us in emergencies. 2. Sound can also be used to help blind people navigate the world better. I’m sorry if these horrible but I tried lol
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2 years ago
Read 2 more answers
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

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2 years ago
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vesna_86 [32]

Answer:

bebe bebe bebe

Explanation:

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