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Free_Kalibri [48]
3 years ago
14

Why would there be a concern with glaciers melting because of global warming?

Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0
The correct answer is C. because it could lead to an increase in ocean levels
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For wach of the following cases, state whether the density of the object increases, decreases, or remains the same:
Ahat [919]

Answer:

a) increases.

b) remains the same.

c) decreases.  the hydrogen molecules constrict or shrink from actual size!

Explanation:

Since ,

Density is given as mass divided by the volume .

( a ) As the Chlorine gas is compressed , the molecules of gas comes close to each other , and hence , the density increases .

( b ) When the lead is taken to high mountain , its density remains the same , as density is independent of higher pressure , as going to mountain will increase the pressure .

( c ) As the water is freeze , its density decreases ,

Because ice is less dense than water , as seen , the ice ice can float on the surface of water .

4 0
3 years ago
5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
How does this graph illustrate Boyle’s law?
bazaltina [42]
Do you have a picture of the graph?
5 0
3 years ago
Anyone know this ? ASAP
GarryVolchara [31]
ASAP stands for as soon  as possible
7 0
3 years ago
6 Fe2+ (aq) + Cr2O72− (aq) + 14 H+ (aq) → 6 Fe3+ (aq) + 2 Cr3+ (aq) + 7 H2O (aq) If the titration of 23 mL of an iron(II) soluti
ratelena [41]

Answer:

1.047 M

Explanation:

The given reaction:

6Fe^{2+}_{(aq)}+Cr_2O_7^{2-}_{(aq)}+14H^+_{(aq)}\rightarrow 6Fe^{3+}_{(aq)}+2Cr^{3+}_{(aq)}+7H_2O_{(aq)}

For dichromate :

Molarity = 0.254 M

Volume = 15.8 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.8 ×10⁻³ L

Thus, moles of dichromate :

Moles=0.254 \times {15.8\times 10^{-3}}\ moles

Moles of dichromate = 0.0040132 moles

1 mole of dichromate react with 6 moles of iron(II) solution

Thus,

0.0040132 moles of dichromate react with 6 × 0.0040132 moles of iron(II) solution

Moles of iron(II) solution = 0.02408 moles

Volume = 23 mL = 0.023 L

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

<u>Molarity = 0.02408 / 0.023 = 1.047 M</u>

7 0
3 years ago
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