Answer:
im not sure but I hope this helps
Explanation:
I believe the equivalents is just the moles reactant/moles limiting reactant
water has a denisty of 1 g/mL. 1 L is 1000 ml so there are 1000g/L.
the molar mass of water is 18g/mol if you use the Liters in the equation above you can find the number of grams present. divide this number you found by 18 to find the moles.
now take the amount of the other reactant given and divide it by its own molar mass. this will give you the number of moles of that reactant.
divide the moles of water by the moles of the reactant and that is the equivalent.
to find the normality you take this number and divide it by the number of liters.
Answer:
Resonance Structures for SCN-:[S-C N]-
Resonance StructureEnergy (kJ/mol)[S-C N]--23.00[S=C=N]
Special properties of water are its high heat capacity and heat of vaporization, its ability to dissolve polar molecules, its cohesive and adhesive properties, and its dissociation into ions that leads to generating pH. Understanding these characteristics of water helps to elucidate its importance in maintaining life.
Answer:
The answer to your question is Gallium-71 = 70.9202 amu
Explanation:
Gallium atomic weight = 69.7
Gallium-69 = 68.9 amu abundance = 60.4%
Gallium-71 = x abundance = 39.6%
To solve this problem just write an equation and solve it for the mass of gallium-71.
Equation
Gallium = Gallium-69(abundance) + Gallium-71(abundance)
Substitution
69.7 = (68.9)(0.604) + Gallium-71(0.396)
69.7 = 41.6156 + Gallium-71(0.396)
Gallium-71(0.396) = 69.7 - 41.6156
Gallium-71(0.396) = 28.0844
Gallium-71 = 28.0844/0.396
Gallium-71 = 70.9202 amu
Answer:
10.5g
Explanation:
First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:
Volume = 250mL = 250/1000 = 0.25L
Molarity = 0.5M
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.5 x 0.25
Mole = 0.125 mole
Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:
Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol
Number of mole of NaHCO3 = 0.125 mole
Mass of NaHCO3 =?
Mass = number of mole x molar Mass
Mass of NaHCO3 = 0.125 x 84
Mass of NaHCO3 = 10.5g
Therefore, 10.5g of NaHCO3 is needed.
