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4 years ago

WILL AWARD BRAINIEST!! Question is in the attached image.

Mathematics

1 answer:

professor190 [17]4 years ago

7 0

Answer:

Look down at explanation

Step-by-step explanation:

First off if it is true in inches you could use a ruler to measure the bottom it works if you are desperate a lot of the time. Also the bottom of the trapezoid is 6 meters. If you didn't know the perimeter you could split the trapezoid into a rectangle and a triangle. You just have to take off the irrelevant sides when you put it together. So you take the 2 meters from the top of the trapezoid and then the bottom of the triangle is 4, so just split up the trapezoid and find the perimeter of the triangle and rectangle.

You might be interested in

The perimeter a rectangle is 46 in if the width of the rectangle is 9 inches what is the length

NeTakaya

The length of the rectangle is 14

<u>steps:</u>

9 + 9 = 18

46 - 18 = 28

28 ÷ 2 = 14

5 0

3 years ago

Please please help!!<br> What X values have points on the graph.. and what are the domains of g(x)??

Phantasy [73]

Domain= [-2,4]
I don’t understand what the first question is asking

7 0

4 years ago

Graph the functions on the same coordinate plane.

beks73 [17]

Answer:

select -3 and 2

Step-by-step explanation:

f(x)=g(x) means set them equal and solve for x

x^2+2x-8=-x^2+4

Add x^2 on both sides and subtract 4 on both sides.

2x^2+2x-12=0

Divide both sides by 2

x^2+x-6=0

Think of two numbers that multiply to be -6 and add up to be 1

that is 3 and -2

so The factored form is (x+3)(x-2)=0

So x=-3 or x=2

7 0

4 years ago

Use the quadratic formula to solve each equation.

Elden [556K]

Answer:

1) $x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}$

$x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}$

2) $x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}$

$x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}$

3) $p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}$

$p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}$

4) $y_1 = \frac{-3 - 9}{4}=-3$

$y_2 = \frac{-3 + 9}{4}= \frac{3}{2}$

Step-by-step explanation:

The quadratic formula is given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

$x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}$

$x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}$

$x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}$

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

$x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}$

$x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}$

$x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}$

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

$p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}$

$p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}$

$p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}$

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

$y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}$

$y_1 = \frac{-3 - 9}{4}=-3$

$y_2 = \frac{-3 + 9}{4}= \frac{3}{2}$

8 0

4 years ago

A car can complete journey of 300 km with the average speed of 60 km per hour how long does it take to complete the journey what

Elden [556K]

Answer:

a. 5 hours

b. 40 kph

Step-by-step explanation:

300 km ÷ 60 km = 5 hours

200 km ÷ 5 hours = 40 kilometers per hour

5 0

3 years ago