1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5

8 0

3 years ago

What is the rate of change of the water level , in feet per hour

miskamm [114]

A; rate of change is the same as slope, so, using the slope formula, $m= \frac{y_{2} - y\1_{1} }{ x_{2} - x_{1} }$ , where $m$ is the slope and $x_{1}$ , $x_{2}$ , $y_{1}$ , and $y_{2}$ are the $x$ and $y$ values.

Plug in $2$ points for $x$ and $y$ , water level being the $y$ and time being the $x$ since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.

$m= \frac{ 30-50}{4-0}$
$m= \frac{-20}{4}$
$m= \frac{-5}{1}$
$m= -5$ ft/hr

4 0

3 years ago

One of the loudest sounds in recent history was that made by the explosion of Krakatoa on August 26-27, 1883. According to barom

liraira [26]

Answer:

150.51 dB

Step-by-step explanation:

Data provided in the question:

decibel level of sound at 161 km distance = 180 dB

d₁ = 161 km

d₂ = 4800 km

I₁ = 180 db

The formula for intensity of sound is given as:

I = $10\log(\frac{I_2}{I_1})$

and the relation between intensity and distance is given as:

I ∝ $\frac{1}{d^2}$

Id² = constant

thus,

I₁d₁² = I₂d₂²

$\frac{I_2}{I_1}=\frac{d_1}{d_2}$

therefore,

I = $10\log(\frac{d_1}{d_2})^2$

I = $10\times2\times\log(\frac{161}{4,800})$

I = 20 × (-1.474)

I = -29.49

Therefore,

the decibel level on Rodriguez Island, 4,800 km away

= 180 - 29.49

= 150.51 dB

8 0

3 years ago

Find the slope and y intercept

RUDIKE [14]

Answer:

Slope: 1/2

y-intercept: -2

8 0

3 years ago