Answer:
water in quarts is in the first jar after 10th pour = 12/11
Step-by-step explanation:
Let X represent first jar and Y represents second jar.
- have two one-quart jars; the first is filled with water, and the second is empty
Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.
Lets give the initial value of 0 to the second as it is empty.
So before any pour, the values are:
X: 2
Y: 0
- pour half of the water in the first jar into the second
After first pour the value of jar X becomes:
Previously it was 2.
Now half of water is taken i.e. half of 2
2 - 1 = 1
So X = 1
The value of jar Y becomes:
The half from jar X is added to second jar Y which was 0:
After first pour the value of jar Y becomes:
0 + 1 = 1
Y = 1
- a third of the water in the second jar into the first
After second pour the value of jar X becomes:
Previously it was 1.
Now third of the water in second jar Y is added to jar X
1 + 1/3
= (3 + 1)/3
= 4/3
X = 4/3
After second pour the value of jar Y becomes:
Previously it was 1.
Now third of the water in Y jar is taken and added to jar X so,
1 - 1/3
= (3 - 1)/3
= 2/3
Y = 2/3
- a fourth of the water in the first jar into the second
After third pour the value of jar X becomes:
Previously it was 4/3.
Now fourth of the water in the first jar X is taken and is added to jar Y
= 3/4 * (4/3)
= 1
X = 1
After third pour the value of jar Y becomes:
Previously it was 2/3
Now fourth of the water in the second jar X is added to jar Y
= 2/3 + 1/4*(4/3)
= 2/3 + 4/12
= 1
Y = 1
- a fifth of the water in the second jar into the first
After fourth pour the value of jar X becomes:
Previously it was 1
Now fifth of the water in second jar Y is added to jar X
= 1 + 1/5*(1)
= 1 + 1/5
= (5+1) / 5
= 6/5
X = 6/5
After fourth pour the value of jar Y becomes:
Previously it was 1.
Now fifth of the water in Y jar is taken and added to jar X so,
= 1 - 1/5
= (5 - 1) / 5
= 4/5
Y = 4/5
- a sixth of the water in the first jar into the second
After fifth pour the value of jar X becomes:
Previously it was 6/5
Now sixth of the water in the first jar X is taken and is added to jar Y
5/6 * (6/5)
= 1
X = 1
After fifth pour the value of jar Y becomes:
Previously it was 4/5
Now sixth of the water in the first jar X is taken and is added to jar Y
= 4/5 + 1/6 (6/5)
= 4/5 + 1/5
= (4+1) /5
= 5/5
= 1
Y = 1
- a seventh of the water in the second jar into the first
After sixth pour the value of jar X becomes:
Previously it was 1
Now seventh of the water in second jar Y is added to jar X
= 1 + 1/7*(1)
= 1 + 1/7
= (7+1) / 7
= 8/7
X = 8/7
After sixth pour the value of jar Y becomes:
Previously it was 1.
Now seventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/7
= (7-1) / 7
= 6/7
Y = 6/7
- a eighth of the water in the first jar into the second
After seventh pour the value of jar X becomes:
Previously it was 8/7
Now eighth of the water in the first jar X is taken and is added to jar Y
7/8* (8/7)
= 1
X = 1
After seventh pour the value of jar Y becomes:
Previously it was 6/7
Now eighth of the water in the first jar X is taken and is added to jar Y
= 6/7 + 1/8 (8/7)
= 6/7 + 1/7
= 7/7
= 1
Y = 1
- a ninth of the water in the second jar into the first
After eighth pour the value of jar X becomes:
Previously it was 1
Now ninth of the water in second jar Y is added to jar X
= 1 + 1/9*(1)
= 1 + 1/9
= (9+1) / 9
= 10/9
X = 10/9
After eighth pour the value of jar Y becomes:
Previously it was 1.
Now ninth of the water in Y jar is taken and added to jar X so,
= 1 - 1/9
= (9-1) / 9
= 8/9
Y = 8/9
- a tenth of the water in the first jar into the second
After ninth pour the value of jar X becomes:
Previously it was 10/9
Now tenth of the water in the first jar X is taken and is added to jar Y
9/10* (10/9)
= 1
X = 1
After ninth pour the value of jar Y becomes:
Previously it was 8/9
Now tenth of the water in the first jar X is taken and is added to jar Y
= 8/9 + 1/10 (10/9)
= 8/9 + 1/9
= 9/9
= 1
Y = 1
- a eleventh of the water in the second jar into the first
After tenth pour the value of jar X becomes:
Previously it was 1
Now eleventh of the water in second jar Y is added to jar X
= 1 + 1/11*(1)
= 1 + 1/11
= (11 + 1) / 11
= 12/11
X = 12/11
After tenth pour the value of jar Y becomes:
Previously it was 1.
Now eleventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/11
= (11-1) / 11
= 10/11
Y = 10/11
