Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
T because all variables are letters
4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
Answer:
b = 5
Step-by-step explanation:
if parallelogram is a rectangle, then the two diagonals has the same length
10/12 x(24/5 x b - 36/5) = 2/3 x (3b + 6)
4b - 6 = 2b + 4
2b = 10
b = 5
Answer:
Therefore the area of the quadrilateral =35 cm²
Step-by-step explanation:
Given, the length of one of diagonal of quadrilateral is 10 cm and perpendicular drawn from the opposite vertices to this diagonal are the length of 2.8 cm and 4.2 cm.
A diagonal divided a quadrilateral into two triangle.
Therefore the area of the quadrilateral
= sum of the area of the triangles
cm² [ area of a triangle
]
=35 cm²
