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3 years ago

The figure shown consists of a rectangle and a parallelogram. Find the area of the entire figure.

Mathematics

2 answers:

nydimaria [60]3 years ago

7 0

Answer:16

Step-by-step explanation:

base times height of both figures then add

Tatiana [17]3 years ago

6 0

Area of a rectangle is Length times Width

Area of a Parallelogram Height time Base

If it was me i would go with A or B

Step-by-step explanation:

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Mark and don are planning to sell each of their marble collections at a garage sale. if don has 4 more than 5 times the number o

natita [175]

Mark and Don have to sell 11 and 59 marbles respectively.

Explanation

Lets assume, the number of marbles Mark has is $x$

As, Don has 4 more than 5 times the number of marbles mark has, so the number of marbles Don has $= 5x+ 4$

Question says that the total number of marbles is 70. So, the equation will be...

$x+(5x+4)= 70\\ \\ 6x+4= 70 \\ \\ 6x = 70-4\\ \\ 6x=66 \\ \\ x= \frac{66}{6}= 11$

So, the number of marbles Mark has = 11

and the number of marbles Don has = $(5*11)+4 = 55+4= 59$

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3 years ago

A box is filled with 400-g packets of noodles. The box weighs 6 kg in total. Three packets are removed from the box. How much do

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The box will weight 4.8 kilograms

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3 years ago

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trasher [3.6K]

No, d depends on g my friend

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2 years ago

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?

Sveta_85 [38]

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ? For what values?(Make sure to use an inequality)

Answer:

y < 3

Step-by-step explanation:

The given two fractions are:

$\frac{7-2y}{6}$ and $\frac{3y-7}{12}$

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

$\frac{7-2y}{6} >\frac{3y-7}{12}$

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

$12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\ 2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y$

This means, for y lesser than 3, the value of first fraction is larger than the second one.

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2 years ago

Simplify Rewrite the expression in the form aⁿ a⋅a⁷=

dem82 [27]

A•a^7 = a^8 (add the power (n=1+7=8))

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3 years ago