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Mashutka [201]
3 years ago
10

Someone that would help me! <33

Physics
1 answer:
avanturin [10]3 years ago
4 0

Answer:

Option A is correct.

Explanation:

In the given triangle , x is the base and 14 is the hypotenuse for angle 33°.

cos 33 = base / hypotenuse

Putting the given values

cos 33 = x / 14

.84 = x / 14

x = .84 x 14

= 11.7

Option A is correct.

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Choose the correct answer
irina1246 [14]

Answer:

The average velocity has magnitude = 10 km/h , direction: east

Explanation:

In order to find the average velocity of the car we need to know the final and initial positions, and the time that took to get from one to the other.

Notice that since its movement was 60 km straight east and then from there 40 km straight west, the car is positioned at 20 km to the east of its initial departure point. therefore the vector change in position is a vector 20 km in magnitude, and direction towards the east.

Since it took the car a total of 1.33 hours plus 0.67 hours to reach its final position, the total time elapsed is: 1.33 + 0.67 hours = 2 hours.

Then,the velocity vector has magnitude; 20 km / 2 hours = 10 km/hour

As we mentioned above. the direction of the velocity vector is east.

6 0
3 years ago
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
olya-2409 [2.1K]

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

5 0
4 years ago
Calculate how much force is required to give a 0.15-kg baseball an acceleration of 12m/s2
Nutka1998 [239]

<u>F = M A </u> (Newton's #2)

Force = (0.15 kg) (12 m/s²)

Force = (0.15 · 12) (kg·m/s²)

<em>Force = 1.8 Newtons</em>

6 0
4 years ago
A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

\sigma_h = 1200psi

And the longitudinal stress would be

\sigma_l = \frac{Pd}{4t}

\sigma_l = \frac{75\times 8}{4\times 0.25}

\sigma_l = 600Psi

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

\tau_{max} = \frac{\sigma_h}{2}

\tau_{max} = \frac{1200}{2}

\tau_{max} = 600Psi

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0
3 years ago
Explain why a moving object cannot come to a stop instantly in zero seconds
sineoko [7]
Well because it has momentum and it needs to be slowed down.
7 0
3 years ago
Read 2 more answers
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