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MrRa [10]
3 years ago
13

the shock absorbers in a car act as a big spring with k= 21900 N/m. when a 92.5 kg person gets in, how far does the spring stret

ch?
Physics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer: 0.04139m

Explanation:

First, we need to calculate the weight of the man which will be:

Weight = mass × acceleration due to gravity

Weight = mg

Weight = 92.5 × 9.8

Weight = 906.5N

Then, we calculate the force which will be:

F = kx

mg = kx

x = mg/k

x = 906.5/21900

x = 0.04139m.

The spring stretched for 0.04139m.

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If a set of displacement vectors laid head to tail make a closed polygon, what is the resultant vector?
Papessa [141]

The resultant vector is zero.

Explanation:

When you add displacement vectors using the head to tail method, you follow this procedure:

- Draw the first vector

- Draw the second vector, with its tail starting from the head of the first vector

- Draw the third vector, with its tail starting from the head of the second vector

.. and so on.

The resultant of the all vectors will be the vector connecting the tail of the 1st vector to the head of the last vector.

In this problem, the vectors make a closed polygon: this means that the head of the last vector coincides with the tail of the first vector.

Therefore, this means that the length of the resultant vector is zero.

Learn more about vector addition:

brainly.com/question/11220787

brainly.com/question/2892784

#LearnwithBrainly

4 0
3 years ago
A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th
Lera25 [3.4K]

"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by <em>ω₀</em>. Then the angular displacement <em>θ</em> at time <em>t</em> is

<em>θ</em> = <em>ω₀t</em> + 1/2 <em>αt</em> ²

while the angular velocity <em>ω</em> is

<em>ω</em> = <em>ω₀</em> + <em>αt</em>

<em />

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2<em>π</em> rad/rev) (38 rev) = 76<em>π</em> rad, as well as to reach an angular velocity of 79 rad/s, so that

76<em>π</em> rad = <em>ω₀</em> (5 s) + 1/2 <em>α</em> (5 s)²

79 rad/s = <em>ω₀</em> + <em>α</em> (5 s)

Solve the second equation for <em>ω₀</em> and substitute into the first equation, then solve for <em>α</em> :

<em>ω₀</em> = 79 rad/s - <em>α</em> (5 s)

==>   76<em>π</em> rad = (79 rad/s - <em>α</em> (5 s)) (5 s) + 1/2 <em>α</em> (5 s)²

==>   76<em>π</em> rad = (79 rad/s) (5 s) - 1/2 <em>α</em> (5 s)²

==>   1/2 <em>α</em> (5 s)² = (79 rad/s) (5 s) - 76<em>π</em> rad

==>   <em>α</em> = ((79 rad/s) (5 s) - 76<em>π</em> rad) / (1/2 (5 s)²)

==>   <em>α</em> ≈ 12.5 rad/s²

3 0
3 years ago
What are the steps of scientific inquiry
lutik1710 [3]
<span>.Ask a Question
.Do Background Research.
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7 0
3 years ago
How could you increase the kinetic thermal energy of a water
eduard

you can increase kinetic thermal energy of the water by boiling it.


5 0
3 years ago
Read 2 more answers
In 1780, in what is now referred to as "Brady's Leap," Captain Sam Brady of the U.S. Continental Army escaped certain death from
zysi [14]

The minimum speed with which Captain Brady had to run off the edge of the cliff to make it safely to the far side of the river is around 6 meters per second.

<h3>Further explanation</h3>

This is a free fall 2-dimensional type of problem, therefor we can write equations for both dimensions which model the fall of captain Brady. Let's call <em>x </em>the distance travelled by the captain on the horizontal direction and <em>y </em>the distance travelled on the vertical direction.

Lets suppose that Brady jumped with a complete horizontal velocity from a point which we will call the origin (meaning zero horizontal and vertical displacement), and let's call <em>ta</em> the time it took for captain Brady to reach the river (meaning the time he spent on the air). The equations of motion for the captain will be:

x= V \cdot t

y= - \frac{g \cdot t^2}{2}

We know that at time <em>ta</em> the captain would have traveled 6.7 m on the horizontal direction, and 6.1 m in the vertical direction. Therefor we can write that:

6.7= V \cdot ta

-6.1= - \frac{g \cdot {ta}^2}{2}

Which gives us a system of 2 equations and 2 unknowns (<em>V</em> and <em>ta</em>). From the second equation we can solve for <em>ta</em> as:

ta = \sqrt{\frac{2 \cdot 6.1}{g}} =1.12 s

And solving for <em>V</em> on the first equation, we find that:

V= \frac{6.7}{1.12} = 5.98 \frac{m}{s}

Which is almost 6 meters per second.

<h3>Learn more</h3>
  • Free fall of an arrow: brainly.com/question/1597396
  • Concept of free fall: brainly.com/question/1708231
<h3>Keywords</h3>

Free fall, projectile, gravity

7 0
3 years ago
Read 2 more answers
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