Answer:
Part a)
Mass of m2 is given as
Part b)
Angular acceleration is given as
Part c)
Tension in the rope is given as
Explanation:
Part a)
When m1 and m2 both connected to the cylinder then the system is at rest
so we can use torque balance here
Part b)
When block m_2 is removed then system becomes unstable
so force equation of mass m1
also we have
now we have
so angular acceleration is given as
Part c)
Tension in the rope is given as
It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
Take the square root of both side
Therefore, it will take 6.42 s for the ball to get to the ground.
Learn more: brainly.com/question/24903556