Answer is A: hydrogen fuel
Answer:
Please see the answer..hope its works
Explanation:
The NMR spectrometer will acquire data for the wrong chemical shift range and you will potentially have skewed data when opening spinworks-NMR spectrometer examines a specific 12 ppm range based on the expected solvent peak, and if a different solvent is used a different range may be examined
To explain further, If the user declares the wrong solvent, one of two things may happen. Firstly, the spectrometer may not be able to establish a deuterium lock and will report an error and not run the sample. Secondly, the spectrometer may be able to establish a lock despite the fact that the deuterium signal is off resonance. If the lock is established, the field strength will be set to a value appropriate to put the declared solvent signal on-resonance. When a proton NMR spectrum is collected, the chemical shift scale will be incorrect by an amount equal to the proton chemical shift difference between the true solvent and the declared solvent.
Answer:
52.79 dm3 of SO2 will be produced when 975kJ/mol of heat are liberated.
Explanation:
In the reaction given;
2PbS(s) + 3O2(g) 2PbO(s) + 2SO2(g) H = -827.4 kJ/mol
-827.4 kJ/mol of heat liberates 2 moles of SO2 in the reaction involving lead and oxygen
At STP, -827.4 kJ/mol of heat liberate 22.4 * 2 dm3 of SO2
So therefore, 975 kJ/mol of heat will liberate
= 975 * 22.4 * 2 / -827.4
= 43 680 / -827.4
= 52.79 dm3 of SO2.
52.79 dm3 of SO2 will be produced at STP if 975 kJ/mol of heat are liberated.
