Ask question

Ask question

All categories

3 years ago

10

64, –48, 36, –27, ... Which formula can be used to describe the sequence? f(x + 1) = 3/4 f(x) f(x + 1) = -3/4 f(x) f(x) = 3/4 f(

x + 1) f(x) = -3/4 f(x + 1)

1 answer:

marysya [2.9K]3 years ago

5 0

Answer:

the formulae given do not make sense.

Step-by-step explanation:

You might be interested in

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

5 0

3 years ago

HELPPPPPPPPPPP! Henley wants to buy a laptop for $1,100. She currently has $110 in savings. Assuming she continues to save 10% o

sammy [17]

Answer:

3months

Step-by-step explanation:

target $1100

currently saved $1100

so we get the amount she need to save to get to the target.

$1100 - $110= $990 Need to be saved

saving rate 10% of $3300= $330 per month

to get the number of months she need to save, we divide amount needed by amount saved per month; $990 ÷ $330= 3months

7 0

3 years ago

What is the median of 70, 85, 79, 88, 95, 80, 100 , 75, 100, and 85?

blondinia [14]

Answer:

85

Step-by-step explanation:

https://www.calculatorsoup.com/calculators/statistics/mean-median-mode.php

4 0

3 years ago

Read 2 more answers

Solve: 3 (x + 4) - 5 (x - 1) <5

agasfer [191]

Answer:

x>6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Zolol [24]

<u><em>Note:</em></u><em> As you have missed to mention the first four terms of the Arithmetic sequence. So, I am randomly assuming that first four terms of the arithmetic sequence be 1, 3, 5, 7... This would anyhow make you understand the concept. So, I am solving your query based on assuming the first four terms of an Arithmetic sequence as 1, 3, 5, 7...</em>

Part A)

<em><u>What is the next term of this sequence?</u></em>

Answer:

${\displaystyle \ a_{5}=9$ is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Step-by-step explanation:

Considering the Arithmetic sequence with fist four terms

<em> 1, 3, 5, 7...</em>

As we know that a sequence is termed as arithmetic sequence of numbers if the difference of any two consecutive terms of the sequence remains constant.

For instance, <em> 1, 3, 5, 7... </em>will be an arithmetic sequence having the common difference 2. Common difference is denoted by 'd'.

So,

Given the sequence

<em>1, 3, 5, 7...</em>

$d=3-1=2,d=5-3=2$

As $a_{1} = 1$ and $d = 2$

The next term i.e. 5th term can be found by using the $nth$ term of the sequence.

So, consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Putting $n=5$ in, $a_{1} = 1$ and $d = 2$ in $\ a_{n}=a_{1}+(n-1)d$ to find the 5th term.

$\ a_{n}=a_{1}+(n-1)d$

$\ a_{5}=1+(5-1)2$

$\ a_{5}=1+(4)2$

${\displaystyle \ a_{5}=9$

So, ${\displaystyle \ a_{5}=9$ is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Part B)

<u><em>Writing down an expression, in terms of n for the nth term of the sequence</em></u>

consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Here, $a_{1}$ is the first term, $d$ is the common difference.

For example,

Given the sequence

<em>1, 3, 5, 7...</em>

$d=3-1=2,d=5-3=2$

As $a_{1} = 1$ and $d = 2$

The next term i.e. 5th term can be found by using the $nth$ term of the sequence.

So, consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Putting $n=5$ in, $a_{1} = 1$ and $d = 2$ in $\ a_{n}=a_{1}+(n-1)d$ to find the 5th term.

$\ a_{n}=a_{1}+(n-1)d$

$\ a_{5}=1+(5-1)2$

$\ a_{5}=1+(4)2$

${\displaystyle \ a_{5}=9$

Keywords: arithmetic sequence, nth term, common difference

Learn more abut arithmetic sequence, nth term and common difference from brainly.com/question/12227567

#learnwithBrainly

7 0

3 years ago