Answer:
38,674.This area represents the increase in population over a 10-year period.
Step-by-step explanation:
When graphed over the interval 0 ≤ t ≤ 10, the birth rate is more than the death rate. This means the area between the two curves is the amount of births subtract the amount of deaths. This results in an area which means the increase of the population.
The birth rate is graphed in green and the death rate is graphed in blue.
To find the area, take the integral of the difference of the functions:
The lowest term is 
.
Solution:
Given expression is 
<u>To reduce this term to the lowest term:</u>
Multiply the numerator and denominator.
Now, divide the numerator and denominator by the greatest common factor.
Here 150 and 8 both have common factor 2.
So, divide numerator and denominator by 2.
Hence the lowest term is .
Answer:
Step-by-step explanation:
Your Welcome!
Answer:
The answer is -33
Step-by-step explanation:
Answer:
- Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
<u>Given expressions</u>
- 4x - x + 5 = 3x + 5
- 8 - 3x - 3 = -3x + 5
Compared, we see the expressions are different as 3x and -3x have different coefficient
<u>Answer options</u>
Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent
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Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
- Incorrect. There are 2 values- variable and constant
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent.
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
