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Dennis_Churaev [7]
3 years ago
9

Which equation has solutions of 6 and -6?

Mathematics
2 answers:
Yanka [14]3 years ago
8 0

Answer D) x2 – 36 = 0

Tom [10]3 years ago
3 0
The answer is d because
x²-36 = 0
x²-6² = 0
(x+6)(x-6) = 0
x = 6, -6
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If the area of a circle is 81π, then what is the diameter of the circle?​
viva [34]

Answer:

18

Step-by-step explanation:

81π=πr^2

r= 9,-9

9+9=18

7 0
3 years ago
Solve For H ---I> A=1/2(B₁+B₂)h
Alex

Answer:

  • h = 2A/(B₁+B₂)

Step-by-step explanation:

<u>Given equation</u>

  • A=1/2(B₁+B₂)h

<u>Solving for h</u>

  • A=1/2(B₁+B₂)h
  • 2A = (B₁+B₂)h
  • 2A/(B₁+B₂)= h
  • h = 2A/(B₁+B₂)

3 0
3 years ago
Cans of tuna cost $3.00 for 6 ½ ounces. At that rate, how much would 104 ounces of tuna cost?
algol13

Answer:

$48.00

Step-by-step explanation:

$3.00 / 6.5 oz = [unknown $] / 104 oz

unknown $ = 104 oz * $3.00 / 6.5 oz

unknown $ = 16 * $3.00 ((oz/oz cancels out))

unknown $ = $48.00

8 0
2 years ago
Read 2 more answers
Help me plzz and thank u sm
vladimir2022 [97]

Answer:

The equation of the axis of symmetry is x = 7

Step-by-step explanation:

Mathematically, we have the equation of the axis of symmetry as;

x = -b/2a

where a is the coefficient of x^2 = 1

b is the coefficient of x which is -14

So, the equation of the axis of symmetry will be;

x = -(-14)/2(1) = 14/2 = 7

So the equation of the axis of symmetry is x =7

6 0
2 years ago
On a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24
Helen [10]

Answer:

30.06 degree Celsius at 4:00 PM.

Step-by-step explanation:

We have been given that on a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24 degrees C. At noon the air conditioner is turned​ off, and the people go home. The temperature outside is a constant 35 degrees C for the rest of the afternoon. The time constant for the building is 5 ​hr. We are asked to find the temperature inside the building at 4:00 PM.

We will use Newton's law of cooling to solve our given problem.

T(t)=M_0+(T_0-M_0)e^{-kt}, where

T(t) = Temperature after t hours.

M_0 = Temperature of surrounding environment,

k = Time constant.

\frac{1}{k}=5\Rightarrow k=\frac{1}{5}

Upon substituting our given values in Newton's cooling law, we will get:

T(t)=35+(24-35)e^{-\frac{t}{5}}

T(t)=35-11e^{-\frac{t}{5}}

To find the temperature at 4:00 pm, we will substitute t=4 in our formula as:

T(4)=35-11e^{-\frac{4}{5}}

T(4)=35-\frac{11}{e^{\frac{4}{5}}}

T(4)=35-\frac{11}{2.2255409284924674}

T(4)=35-4.9426186052894379601

T(4)=30.05738139471

T(4)\approx 30.06

Therefore, the temperature inside building would be approximately 30.06 degree Celsius at 4:00 PM.

5 0
3 years ago
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