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alisha [4.7K]
3 years ago
13

Mrs. Brown drove 105 miles in 2.5 hours. What was Mrs. Browns speed in miles per hour?

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

42mph.

Step-by-step explanation:

We know that the formula for miles per hour is.

r = d/t

R is our rate or miles per hour.

D is our distance.

T is our time.

In this case our distance is 105 miles.

And our times is 2.5 hours.

Therefore if we substitute them into our formula:

105mi ÷ 2.5hrs = 42mph

Hope this helped!

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Identify the graphed linear equation.<br> A) y=5x+2<br> B) y=5x-2<br> C) y=-5x+2<br> D) y=-5x-2
soldi70 [24.7K]

Answer: y=-5x-2

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7 0
3 years ago
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5
miskamm [114]

Answer:  

z=-3.25

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=5.24 represent the mean production for the sample  

\sigma=0.32 represent the sample standard deviation for the sample  

n=16 sample size  

\mu_o =5.5 represent the value that we want to test  

\alph=0.05a represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean production is different from 5.5 tons, the system of hypothesis would be:  

Null hypothesis:\mu =5.5  

Alternative hypothesis:\mu \neq 5.5  

If we analyze the info given we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{5.24-5.5}{\frac{0.32}{\sqrt{16}}}=-3.25  

P-value

Since this is a two side test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the production its significant different compared to the desired percentage of SiO2 of 5.5 at 5% of signficance.  

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3 years ago
Inequality help!<br><br>so I'm thinking it's choice one...would that be right?
professor190 [17]
The answer is choice 1
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3 years ago
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