Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80
444.3 = (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 /10 )
Answer
A. (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 /10 )
It's 192, I'm pretty sure. I hope that you get this right! :^)
Answer:
x = -6
-18+4y=0 => 4y=18 =>y=18/4=9/2
Y=5
3x+20=0 => x=3x= -20=> x= -20/3
Step-by-step explanation:
Answer:
X = -29/10
Step-by-step explanation: