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bekas [8.4K]
3 years ago
13

Maia says that both lines on this position vs time graph show acceleration. Is she correct? Why or why not?

Physics
2 answers:
Ulleksa [173]3 years ago
3 0

Answer:

do you have access to the graph?

Explanation:

tankabanditka [31]3 years ago
3 0

Answer:

Maia is not correct because a straight line moving upwards on a position vs time graph has a constant slope, so it represents constant velocity. No change in velocity means no acceleration is taking place.

Explanation:

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1, 2 and 4 apply. im not sure that 2 ALWAYS applies though.
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Help REALL FAST PLEASE
Pepsi [2]

Answer:

acceleration

Explanation:

Even though the initial and final speeds are the same, there has been a change in direction for the object

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Which of the following is NOT a characteristic of electromagnetic light waves?
bearhunter [10]

Answer:

A. They can be reflected and refracted

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If Grant starts at one end of the pool and swims 3 3/4 laps before stopping, his distance traveled is _______ and his displaceme
iragen [17]

Answer:

<em>Distance= 187.5 m </em>

<em>Displacement= 12.5 m</em>

Explanation:

<u>Distance And Displacement </u>

The question doesn't say what the length of the pool is, so we are assuming two things:

The pool is 50 m long.

One lap is one pool length, i.e. 50 m

Grant swims 3 3/4 laps. If we add up the total distance is 50*(3.75)=187.5 m

Grant starts in one end, swims one pool, then swims back one pool. Right now, he has zero displacement

Then he swims another pool and returns only 3/4 of the lap, which means he still needed 1/4*50 m=12.5 to arrive at his starting point. The final displacement is the subtraction of the final position minus the initial position, i.e. 12.5 m - 0 m= 12.5 m

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6 0
3 years ago
How do i solve A sound wave has a frequency of 658 Hz in air
kiruha [24]

Answer:

-47 °C

Explanation:

Speed of sound in air at sea level is:

v = 331 m/s + 0.6 m/s/°C T

where T is the temperature in Celsius.

The speed of sound is also the frequency times the wavelength:

v = fλ

Therefore:

fλ = 331 m/s + 0.6 m/s/°C T

(658 Hz) (0.46 m) = 331 m/s + 0.6 m/s/°C T

302.68 m/s = 331 m/s + 0.6 m/s/°C T

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T = -47.2 °C

Rounding to two significant figures, the temperature is -47 °C.

6 0
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