Question

A taxi is travelling at 15m/s. Its driver accelerates with acceleration 3m/s^2 for 4 s. What would be the new velocity?..... pls answer with an explanation.​

Answer 1

Answer:

27 m/s

Explanation:

Given:

v₀ = 15 m/s

a = 3 m/s²

t = 4 s

Find: v

v = at + v₀

v = (3 m/s²) (4 s) + (15 m/s)

v = 27 m/s

Answer 2

Answer:

The final speed of the taxi is 27 m/s.

Explanation:

Given data

• Initial speed (v₀):  15 m/s

• Acceleration (a): 3 m/s²

• Time (t): 4 s

We can find the final speed (vf) using the following kinematic expression.

vf = v₀ + a × t

vf = 15 m/s + 3 m/s² × 4 s

vf = 15 m/s + 12 m/s

vf = 27 m/s

The final speed of the taxi is 27 m/s.