Answer:
D
Explanation:
F = G m1 m2 / r^2 now double r
F = G m1m1/ (2r)^2
F = 1/4 G m1m2/r^2 <===== this is 1/4 of the original
Explanation:
It is given that,
Mass of platinum bar, m = 750 g
Length of the bar, l = 5 cm
Breadth of the bar, b = 4 cm
Width of the bar, h = 1.5 cm
Volume of the bar, 

We need to find the density of the platinum bar. The density of any substance is given by :



So, the density of the platinum bar
. Hence, this is the required solution.
Answer:
a) 1.06*10^-5
b) 0.00105 °C^-1
Explanation:
Given that
Length of the cylinder, L = 1.5 m
Radius of the cylinder, r = 0.25 cm
Voltage across the rod, V = 15 V
I• at Temperature T• = 20° C is 18.5 A
I at Temperature T = 90° C is 17.2 A
See attachment for calculations
Answer:
work done would be I don't know