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3 years ago

8

Can you help me plz ?

2 answers:

Alexxx [7]3 years ago

7 0

Given: 30 total days and there were 6 days with rain with a temperature below 70 degrees

To find the percentage, divide the part (6 days) by the whole (30 days) then multiply the quotient by 100.

(6 days / 30 days) x 100 = 20%

20% of the days in June had a temperature below 70 degrees and had rain.

Nonamiya [84]3 years ago

3 0

Answer: 20%

Step-by-step explanation:

Looking at the chart we can see that there were 6 days with a temperature below 70 and with rain.

If you add all the numbers in the chart you get a total of 6 + 2 + 14 + 8 = 30 days

Now that we know the total number of days and the days to find a percentage for, we can find the percentage by dividing those specified days by the total (specified days/total days) and multiplying by 100 to get the answer in percentage form

So set up a fraction where (6 / 30) * 100 is the percent

and you get 20%

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Find the total surface area.

marysya [2.9K]

Answer:

143.4 mi²

Step-by-step explanation:

Top: 8x6=48

Bottom: 3x8=24

Sides: 3x8=24 and 24

Trapezoids sides: (6+3)/2*2.6=4.5*2.6=11.7 and 11.7

TOTAL: 48+24+24+24+11.7+11.7= 143.4 mi²

5 0

4 years ago

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

2.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

3.

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

4.

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

5.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers

Select all the correct answers.

ankoles [38]

Answer:

3.844 x 10^5

3.844E-5

3.844 × 10-5 kilometers

Step-by-step explanation:

8 0

3 years ago

Amanufacturer of potato chips would like to know whether its bag filling machine works correctly at the 433 gram setting. It is

ankoles [38]

Answer:

There is not enough evidence to support the claim that the bags are under filled.

Step-by-step explanation:

Given :

Population mean, μ = 433

Sample size, n = 26

xbar = 427

Variance, s² = 324 ; Standard deviation, s = √324 = 18

The hypothesis :

H0 : μ = 433

H0 : μ < 433

The test statistic :

(xbar - μ) ÷ (s/√(n))

(427 - 433) / (18 / √26)

-6 / 3.5300904

T = -1.70

The Pvalue :

df = 26-1 = 25 ; α = 0.05

Pvalue = 0.0508

Since Pvalue > α ; WE fail to reject the Null and conclude that there is not enough evidence to support the claim that the bags are underfilled

3 0

3 years ago

20 is what percent of 50

AleksAgata [21]

The answer to the equation is 30%

3 0

3 years ago