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3 years ago

What is the value of the blue dot

Mathematics

2 answers:

pshichka [43]3 years ago

7 0

Answer:

Step-by-step explanation:

8,10,12. There is one space in between 8 and 12 where the count has increased by 2. If we continue this then we get 14,16, 18, and finally 20.

Gre4nikov [31]3 years ago

4 0

Answer:

there doesnt seem to be much information, but from what it looks like it looks like it is 20?

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A cylinder’s volume must be 850 cubic feet while the radius of the cylinder cannot exceed 6 feet. What is the smallest possible

Neporo4naja [7]

I think it's B. not sure though u should wait. till someone else answer to see if I am right

6 0

3 years ago

A pet toy manufacturer is designing a plastic ball for dogs that will float in water. In order for the ball to float it must hav

algol13

Answer:

3.576 cm

Step-by-step explanation:

radius of ball, r=?

Given:

Density, p = 0.600g/mL

mass, m= 115g

finding volume, v of ball by using formula p=m/v

v= m/p

= 115/0.600

=191.666 mL^3

=191.666 cm^3

Now using formula v= (4/3)πr^3 to find radius, r of the ball

r^3= 3v/4π

= 3(191.666)/4π

=45.75 cm

r =3.5767 cm !

7 0

3 years ago

What is the product of R and T equals r = 5.33 and T equals 0.5

Veseljchak [2.6K]

I believe you just multiply the two numbers together and get 2.665

3 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

4/9 = 13/q<br><br> I'm supposed to solve it and round it to the nearest hundredth if necessary

Elodia [21]

Answer:

5.78

Step-by-step explanation:

Multiply 13 to both sides to get q by itself

4/9*13=q

this gives you

5.77777778=q

but we need to round it to the nearest hundredth

5.78

8 0

3 years ago